Python打印不需要的额外换行符

Question

为什么当我运行下面的代码时，Python总是打印额外的换行符？我试图重新编写代码以消除任何意外的空白，但它仍然会打印出一个额外的新行。有人知道为什么谢谢。

def main(): 
    names_in()       #This function import the file and read all the content and put the content into a list. 

    print_names(names_in)  # Before the names are sorted. 

def names_in(): 
    infile = open('names.txt','r') 
    names_list = []     #empty list. 
    names = infile.readline() # read contents. 

    #loop for continue to read. 
    while names != '': 
     names = infile.readline()  #continue to the next name. 
     names = names.rstrip('\n') #return a copy of the string which all \n has been stripped from the end of the string. 
     names_list.append(names) #write names in the file into a list. 
    infile.close() 

    return names_list      #return the list back to the function. 



def print_names(names_in):  #This function will print out the names in the list one per line, single-spaced. 
    for item in names_in(): 
     print(item) 


main() 

这在我的输入文件：

Riggs, Jerry 
Stone, Ruby 
Wood, Holly 
Dover, Ilene 
Funt, Ella 
Storm, Wayne 
Lowe, Lyle 
Free, Bjorn 
Caine, Candy 
Carr, Rex 
Downs, Mark 
Twain, Lionel 
Thorn, Rose 
Shore, Rocky 
Bush, Rose 
Waters, Muddy 
Graves, Doug 
Stone, Roxanne 
Rivers, Wade 

Answer 1

你的代码打印额外的换行符的原因是因为在names_in功能的最后一次迭代中，变量names是``，它被附加到names_list的末尾，导致print_names函数在最后运行print ''，这会打印一个额外的换行符。