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我有下面这些代码进出口试图使成圆形图使用R:在circlize图调整标签
我已阅读vigenette,承认它的一些已经在我头上有点惊人的包circlize ,
我想知道是否有一个快速的方法来删除我的图表上的所有标签,包括刻度标记,并且只需按照与这个扇区相同的角度在浅灰色中添加回奥迪,沃尔沃和宝马example
library (dplyr)
library(circlize)
df = read.table(textConnection("
Brand_from model_from Brand_to Model_to
VOLVO s80 BMW 5series
BMW 3series BMW 3series
VOLVO s60 VOLVO s60
VOLVO s60 VOLVO s80
BMW 3series AUDI s4
AUDI a4 BMW 3series
AUDI a5 AUDI a5
"), header = TRUE, stringsAsFactors = FALSE)
# Add customer satisfaction (1 being positive, 0 being negative)
df <- df %>%
mutate(Customer.Sat = c("POS","NEG","NEG","POS","POS","NEG","NEG")) %>%
select(Brand_from,Brand_to,Customer.Sat)
# Set the colour Scheme for the association
col = c("NEG" = "red",
"POS" = "green")
diffHeight = c("POS" = -0.02,
"NEG" = 0.04)
# Build the Chord Diagram
chordDiagram(df[1:2],
col = col[df$Customer.Sat],
diffHeight = diffHeight[df$Customer.Sat])
circos.clear()
我看到有可能使用我所见过的答案Rotate labels in a chordDiagram (R circlize)这是非常相似
然而,这并不删除现有的标签,如刻度线和部门的名称代码
# Rotates the Labels so they are 90 Degrees to the chord diagram
circos.trackPlotRegion(track.index = 1, panel.fun = function(x, y) {
xlim = get.cell.meta.data("xlim")
ylim = get.cell.meta.data("ylim")
sector.name = get.cell.meta.data("sector.index")
circos.text(mean(xlim), ylim[1] + .1, sector.name, facing = "clockwise", niceFacing = TRUE, adj = c(0, 0.5))
circos.axis(h = "top", labels.cex = 0.5, major.tick.percentage = 0.2, sector.index = sector.name, track.index = 2)
}, bg.border = NA)
嗨lukeA谢谢你,你能解释一下代码吗,这样我就可以在将来更容易地拍出更复杂的例子.....感谢你的时间 –
你会在小插曲中找到一个解释:https: //cran.r-project.org/web/packages/circlize/vignettes/visualize_relations_by_chord_diagram.pdf#page=16 – lukeA