通过注释中使用Hibernate UUIDGenerator

Question

我用我的UUID如下：

@Id 
@GeneratedValue(generator = "uuid") 
@GenericGenerator(name = "uuid", strategy = "uuid") 
@Column(name = "uuid", unique = true) 
private String uuid; 

，但我得到一个智能休眠警告：

使用 org.hibernate.id.UUIDHexGenerator 这不会生成符合UUID值的IETF RFC 4122 ;考虑使用 org.hibernate.id.UUIDGenerator代替

所以我想切换到org.hibernate.id.UUIDGenerator，现在我的问题是我应该怎么告诉它Hibernate的发电机。我看到一些人用它作为一个“休眠的UUID” - 所以这是我尝试过，但阴性结果：

@Id 
@GeneratedValue(generator = "hibernate-uuid") 
@GenericGenerator(name = "hibernate-uuid", strategy = "hibernate-uuid") 
@Column(name = "uuid", unique = true) 
private String uuid; 

Answer 1

它应该是uuid2：

... 
@GenericGenerator(name = "uuid", strategy = "uuid2") 
... 

见5.1.2.2.1. Various additional generators。

Answer 2

HibernateDoc说，你可以使用下列内容：

@Id 
@GeneratedValue(generator="system-uuid") 
@GenericGenerator(name="system-uuid", strategy = "uuid") 
@Column(name = "uuid", unique = true) 
private String uuid; 

我希望你使用Hibernate 3.5。

Answer 3

的Try ...

@Id 
@GeneratedValue(generator = "uuid2") 
@GenericGenerator(name = "uuid2", strategy = "uuid2") 
@Column(name = "uuid", columnDefinition = "BINARY(16)") 
public UUID getId() 
{ 
    return id; 
} 

public void setId(UUID i) 
{ 
    id = i; 
} 

注意 “UUID2”，而不是 “的uuid”。

Answer 4

未知Id.generator：休眠的UUID

@Id 
@GeneratedValue(generator = "uuid") 
@GenericGenerator(name = "uuid", strategy = "org.hibernate.id.UUIDGenerator") 
@Column(name = "id", unique = true) 
public String getId() { 
    return id; 
} 

public void setId(String id) { 
    this.id = id; 
}