2013-05-02 110 views
5

我有三个表和我需要总额分开。此外,我将使用选择或where子句的字段。Mysql左连接和总和

SELECT i.*, x.* FROM items AS i 
LEFT JOIN 
(
    SELECT 
    p.item_id 
    ,SUM(p.amount) AS saleAmount 
    ,SUM(IF(p.type=1,pa.amount,0)) AS paidAmount 
    FROM payments AS p 
    LEFT JOIN payment_actions AS pa ON pa.payment_id=p.id 
    GROUP BY p.id 
) AS x ON x.item_id=i.id 

items table;

id 
--- 
1 

付款表;

id | item_id | amount 
--------------------------- 
1 | 1  | 300 

payment_actions表;

id | payment_id | amount 
--------------------------- 
1 | 1   | 100 
1 | 1   | 50 

结果应该是;

saleAmount | paidAmount 
-------------------------- 
    300  | 150 
+0

什么是你想要的输出,并请张贴一些示例数据的简单方法? – 2013-05-02 11:13:06

+0

我更新了问题 – 2013-05-02 11:19:17

回答

11

这里是你想要的结果

SELECT 
    i.id, 
    p.amount, 
    pa.amount 
FROM items AS i 
    LEFT JOIN (SELECT 
      id, 
      item_id, 
      SUM(amount) amount 
     FROM payments 
     GROUP BY item_id) AS p 
    ON p.item_id = i.id 
    LEFT JOIN (SELECT 
      payment_id, 
      sUM(amount) amount 
     FROM payment_actions) AS pa 
    ON pa.payment_id = p.id 
group by i.id 
+0

如果payment_actions有两条记录,则记录重复付款,因此saleAmount = 600。 saleAmount应为300 – 2013-05-02 11:36:15

+0

@MertEmir我编辑了可以测试的查询 – 2013-05-02 11:47:00

+0

payment_id是付款表上的id字段。不是项目表:( – 2013-05-02 11:56:04