我又回来了。 我之前曾问过一个类似的问题,但即使在前一个anwser的帮助下,并用questionmarks尝试它,而不是添加我尝试过AddWithValue,我没有任何运气。SQL ASP.NET INSERT麻烦(第2部分)
我试图将txt_Naam更改为txt_Naam.Text,什么都没有。
同时把[]围绕在列名上,没有运气。 它不断给我这个“INSERT INTO语句中的语法错误。”。
这次我没有得到下面的代码。 可能是小事,但我无法弄清楚。 (再次...)
protected void btn_final_Click(object sender, EventArgs e)
{
string fact_adres = txt_Naam.Text + "," + txt_Anaam.Text + "," + txt_Adres.Text + "," + txt_Toevoeg.Text + "," + txt_Pcode.Text + "," + txt_Plaats.Text + "," + txt_Email.Text ;
string fact_adres1 = txt_Naam1.Text + "," + txt_Anaam1.Text + "," + txt_Adres1.Text + "," + txt_Toevoeg1.Text + "," + txt_Pcode1.Text + "," + txt_Plaats1.Text + "," + txt_Email1.Text;
string a = "1";
OleDbConnection conn = new OleDbConnection();
conn.ConnectionString = "Provider=Microsoft.ACE.OLEDB.12.0; "
+ "Data Source=|DataDirectory|webwinkel.accdb";
OleDbCommand cmd = new OleDbCommand();
cmd.Connection = conn;
cmd.CommandText = "INSERT INTO Order (factuur_adres_id, verzend_adres_id, totaalprijs) VALUES (?, ?, ?);";
cmd.Parameters.Add("@factuur_adres", OleDbType.VarChar, 125).Value = fact_adres;
cmd.Parameters.Add("@verzend_adres", OleDbType.VarChar, 125).Value = fact_adres1;
cmd.Parameters.Add("@totaal_prijs", OleDbType.VarChar, 7).Value = a;
try
{
conn.Open();
OleDbDataReader reader = cmd.ExecuteReader();
reader.Close();
}
catch (Exception exc)
{
Label1.Text = exc.Message;
}
finally
{
conn.Close();
Session["Winkelwagen"] = null;
}
}
我试过了,它仍然给我错误。这就是为什么我将它改为questionmarks。 – 2012-07-18 21:03:38
@ Big.S你现在得到了什么错误? – 2012-07-18 21:04:21
@ Big.S在你的sql服务器上运行上面的查询并检查它是否在那里工作?语法是正确的。 – 2012-07-18 21:08:44