MySQL数据库查询与if条件

Question

我有一个表名视频

表视频

id name upload_date 

1 one  1408336348 
2 two  1409884215 

现在我要选择，如果上传的最后2天之间的视频，然后是所有的数据也计算或没有

结果像

id name upload_date new 

1 one  1408336348 no 
2 two  1409884215 yes 

我使用这个查询，但无法工作

SELECT v.*,(if(from_unixtime(v.upload_date) < NOW() - INTERVAL 2 DAY) then 'no' else 'yes') 
AS new FROM `video` as v 

查询返回错误

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ') then 'no' else 'yes') 
AS new FROM `video` as v 
LIMIT 0, 25' at line 1 

Answer 1

尝试使用情况

SELECT v.* 
    ,case 
     when (from_unixtime(v.upload_date) < NOW() - INTERVAL 2 DAY) then 'yes' 
     else 'no') 
    end AS new 
FROM `video` as v 

Answer 2

这不是在一个MySQL的IF正确的语法。试着这样说：

SELECT v.*, 
    IF(from_unixtime(v.upload_date) < NOW() - INTERVAL 2 DAY, 'yes', 'no') AS new 
FROM `video` as v 

Answer 3

问案声明：

SELECT v.*, 
    CASE WHEN from_unixtime(v.upload_date) < NOW() - INTERVAL 2 DAY 
     THEN 'Yes' 
     ELSE 'No' 
    END AS new 
FROM `video` 

这是ANSI标准的方式做到这一点的SQL。