Python-Tkinter-Basic登录表单

我正在尝试制作一个基本登录表单。我在将值传递给检查用户名和密码的函数时遇到了问题。Python-Tkinter-Basic登录表单

这里是我的代码：

from tkinter import * 

class Application(Frame): 
    def __init__(self,master): 
     super(Application, self).__init__(master)#Set __init__ to the master class 
     self.grid() 
     self.create_main()#Creates function 

    def create_main(self): 
     print("testing") 
     self.title = Label(self, text=" Stuck In The Circle ")#TITLE 
     self.title.grid(row=0, column=2) 

     self.user_entry_label = Label(self, text="Username: ")#USERNAME LABEL 
     self.user_entry_label.grid(row=1, column=1) 

     self.user_entry = Entry(self)      #USERNAME ENTRY BOX 
     self.user_entry.grid(row=1, column=2) 

     self.pass_entry_label = Label(self, text="Password: ")#PASSWORD LABEL 
     self.pass_entry_label.grid(row=2, column=1) 

     self.pass_entry = Entry(self)      #PASSWORD ENTRY BOX 
     self.pass_entry.grid(row=2, column=2) 

     self.sign_in_butt = Button(self, text="Sign In",command = self.logging_in)#SIGN IN BUTTON 
     self.sign_in_butt.grid(row=5, column=2) 

    def logging_in(self): 
     print("hi") 
     user_get = user_entry.get()#Retrieve Username 
     pass_get = pass_entry.get()#Retrieve Password 

     if user_get == 'sam': 
      if pass_get == '123': 
       print("Welcome!") 






#Main 
root = Tk() 
root.title("Stuck in the Circle") 
root.geometry("400x100") 

app = Application(root)#The frame is inside the widgit 
root.mainloop()#Keeps the window open/running

这是我的错误：

Exception in Tkinter callback Traceback (most recent call last): File "C:\Users\Sam\AppData\Local\Programs\Python\Python35-32\lib\tkinter_init_.py", line 1549, in call return self.func(*args) File "C:/Users/Sam/Desktop/Computer Science/Python/Python- Modules/Tkinter/Tkinter Projects/Login Form GUI.py", line 31, in logging_in user_get = user_entry.get()#Retrieve Username NameError: name 'user_entry' is not defined

来源

2016-01-21 Sam Stacey

这是我的错误： –

异常Tkinter回调回溯（最近呼叫最后）：文件“C：\ Users \ Sam \ AppData \ Local \ Programs \ Python \ Python35-32 \ lib \ tkinter \ __ init__.py” ，第1549行，__call__ return self.func（* args）文件“C：/ Users/Sam/Desktop/Computer Science/Python/Python- Modules/Tkinter/Tkinter Projects/Login Form GUI.py”，第31行，在logging_in user_get = user_entry.get（）＃取回用户名 NameError：名称'user_entry'未定义 –

可能的重复[如何将TKinter与Python登录屏幕？]（https://stackoverflow.com/问题/ 28156719/how-can-i-integrate-tkinter-with-python-log-in-screen） –

def logging_in(self): 
    print("hi") 
    user_get = self.user_entry.get()#Retrieve Username 
    pass_get = self.pass_entry.get()#Retrieve Password

使用self.user_entry.get()

当你调用类变量，你需要调用它self.variable_name

来源

2016-01-21 19:38:18

非常感谢你！我一直在这个工作了几个小时，我觉得很愚蠢！代码全部按照我想要的方式工作。我非常感谢你的帮助：D祝你有美好的一天！ –

没问题:)当你有机会时请选择最好的答案！ –

Python-Tkinter-Basic登录表单

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