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对,所以我有点卡住试图检索使用.substring的最后一个字母。如果我输入例如“100C”,它将正常工作,变量celOrFar将=“C”。但是,用户应该在数字后插入一个空格,但这样做会给我一个不正确的结果。 “100 C”会给我“0”而不是C,“1234 5678C”会给我4!我仍然是Java的初学者,所以任何帮助表示赞赏!试图检索包含空格的字符串的最后一个字母
public static void stateOfWater() {
System.out.println("Enter a temperature followed by a space and C/F: ");
String userInput = input.next();
String celOrFar = userInput.substring(userInput.length()-1);
String degreeString = userInput.trim();
degreeString = degreeString.replace("C", "");
degreeString = degreeString.replace("F", "");
degreeString = degreeString.replace("f", "");
degreeString = degreeString.replace("c", "");
int degree = Integer.parseInt(degreeString);
if (celOrFar.equals("C")|| celOrFar.equals("c")) {
if (degree <= 0) {System.out.println("Your water is a solid at " +userInput);}
if (degree >= 100) {System.out.println("Your water is a gas at " +userInput);}
if (degree >0 && degree <100) {System.out.println("Your water is a liquid at " +userInput);}
}
if (celOrFar.equals("F") || celOrFar.equals("f")) {
if (degree <= 32) {System.out.println("Your water is a solid at " +userInput);}
if (degree >= 212) {System.out.println("Your water is a gas at " +userInput);}
if (degree >32 && degree <212) {System.out.println("Your water is a liquid at " +userInput);}
}
}
扫描器使用空格作为分隔符,您应该阅读[doc](https://docs.oracle.com/javase/8/docs/api/java/util/Scanner.html) –