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我想同时插入记录和上传文件,现在我正在使用FreeASPUpload脚本。当我提交表单,它返回该错误如何使用FreeASPUpload脚本插入记录和上传文件
Cannot use the generic Request collection after calling BinaryRead
这里是我的网页
<%
option explicit
Response.Expires = -1
Server.ScriptTimeout = 600
Session.CodePage = 65001
%>
<!-- #include file="UploadClass.asp" -->
<%
Dim uploadsDirVar
uploadsDirVar = server.MapPath("Files_Uploaded")
function OutputForm()
%>
<form name="frmSend" method="POST" enctype="multipart/form-data" accept-charset="utf-8" action="form.asp" onSubmit="return onSubmitForm();">
<input type="hidden" name="ApplicationForm" value="Insert" />
Name: <input type="text" name="name_insert" value="" size="30" />
<B>File names:</B><br>
File 1: <input name="attach1" type="file" size=35><br>
<br>
<input style="margin-top:4" type="submit" value="Submit">
</form>
<%
end function
function TestEnvironment()
Dim fso, fileName, testFile, streamTest
TestEnvironment = ""
Set fso = Server.CreateObject("Scripting.FileSystemObject")
if not fso.FolderExists(uploadsDirVar) then
TestEnvironment = "<B>Folder " & uploadsDirVar & " does not exist.</B><br>The value of your uploadsDirVar is incorrect. Open uploadTester.asp in an editor and change the value of uploadsDirVar to the pathname of a directory with write permissions."
exit function
end if
fileName = uploadsDirVar & "\test.txt"
on error resume next
Set testFile = fso.CreateTextFile(fileName, true)
If Err.Number<>0 then
TestEnvironment = "<B>Folder " & uploadsDirVar & " does not have write permissions.</B><br>The value of your uploadsDirVar is incorrect. Open uploadTester.asp in an editor and change the value of uploadsDirVar to the pathname of a directory with write permissions."
exit function
end if
Err.Clear
testFile.Close
fso.DeleteFile(fileName)
If Err.Number<>0 then
TestEnvironment = "<B>Folder " & uploadsDirVar & " does not have delete permissions</B>, although it does have write permissions.<br>Change the permissions for IUSR_<I>computername</I> on this folder."
exit function
end if
Err.Clear
Set streamTest = Server.CreateObject("ADODB.Stream")
If Err.Number<>0 then
TestEnvironment = "<B>The ADODB object <I>Stream</I> is not available in your server.</B><br>Check the Requirements page for information about upgrading your ADODB libraries."
exit function
end if
Set streamTest = Nothing
end function
function SaveFiles
Dim Upload, fileName, fileSize, ks, i, fileKey
Set Upload = New FreeASPUpload
Upload.Save(uploadsDirVar)
' If something fails inside the script, but the exception is handled
If Err.Number<>0 then Exit function
SaveFiles = ""
ks = Upload.UploadedFiles.keys
if (UBound(ks) <> -1) then
SaveFiles = "<B>Files uploaded:</B> "
for each fileKey in Upload.UploadedFiles.keys
SaveFiles = SaveFiles & Upload.UploadedFiles(fileKey).FileName & " (" & Upload.UploadedFiles(fileKey).Length & "B) "
next
else
SaveFiles = "No file selected for upload or the file name specified in the upload form does not correspond to a valid file in the system."
end if
SaveFiles = SaveFiles & "<br>Enter a number = " & Upload.Form("enter_a_number") & "<br>"
SaveFiles = SaveFiles & "Checkbox values = " & Upload.Form("checkbox_values") & "<br>"
SaveFiles = SaveFiles & "List values = " & Upload.Form("list_values") & "<br>"
SaveFiles = SaveFiles & "Text area = " & Upload.Form("t_area") & "<br>"
end function
%>
<HTML>
<HEAD>
<TITLE>Test Free ASP Upload 2.0</TITLE>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<style>
BODY {background-color: white;font-family:arial; font-size:12}
</style>
<script>
function onSubmitForm() {
var formDOMObj = document.frmSend;
if (formDOMObj.attach1.value == "")
alert("Please press the Browse button and pick a file.")
else
return true;
return false;
}
</script>
</HEAD>
<BODY>
<br><br>
<div style="border-bottom: #A91905 2px solid;font-size:16">Upload files to your server</div>
<%
Dim diagnostics
if Request.ServerVariables("REQUEST_METHOD") <> "POST" then
diagnostics = TestEnvironment()
if diagnostics<>"" then
response.write "<div style=""margin-left:20; margin-top:30; margin-right:30; margin-bottom:30;"">"
response.write diagnostics
response.write "<p>After you correct this problem, reload the page."
response.write "</div>"
else
response.write "<div style=""margin-left:150"">"
OutputForm()
response.write "</div>"
end if
else
response.write "<div style=""margin-left:150"">"
OutputForm()
response.write SaveFiles()
response.write "<br><br></div>"
end if
%>
</BODY>
</HTML>
<!-- #include file="ADOVBS.inc" -->
<%
'=======================================================================================
' CONNECT DATABASE
'=======================================================================================
Dim objConn, objRs
Set objConn = CreateObject("ADODB.Connection")
Set objRs = CreateObject("ADODB.Recordset")
objConn.open"Provider=Microsoft.Jet.OLEDB.4.0;Data Source="& server.MapPath("db/Job_database.mdb") &";Mode=ReadWrite|Share Deny None;Persist Security Info=False"
If Request("ApplicationForm") = "Insert" Then
Set InsCom=Server.CreateObject("ADODB.Command")
InsCom.ActiveConnection=objConn
InsName = Trim(request("name_insert"))
InsName = replace(InsName,"'","''")
InsCom.CommandText = "Insert into applications(aname)Values(?)"
InsCom.Parameters.Append InsCom.CreateParameter("@name_insert", adVarChar, adParamInput, 255, InsName)
InsCom.Execute
End If
%>
我一直在寻找这个问题的完整的源代码,但不能使它工作。尽管我发现我必须使用FreeASPUpload提供的Form Collection
。因此我改变
If Request("ApplicationForm") = "Insert" Then
这个
If Upload.Form("ApplicationForm") = "Insert" Then
但它也返回一个错误,即说:变量未定义:“上传”
如果我改变请求方法,它只上传文件不插入记录
If Request.QueryString("ApplicationForm") = "Insert" Then
什么我的理解是,我的插入查询是在错误的地方左右...
请帮我解决这个问题..谢谢
非常感谢John,我已经按照你的建议移动了所有的代码。但是有一个问题,虽然'ADOVBS.INC'在这个文件中定义的变量没有被识别,因为我把文件移动到'UploadClass.asp'下面,但是明确地声明它们完成了工作。所以再次非常感谢你,现在我的问题解决了:) – yaqoob
很高兴你到了那里。我想你也可以在函数本身中包含adovbs.inc,但声明你需要的唯一变量是一个整洁的解决方案IMO。我很少使用adovbs.inc – John
几件事** 1。**使用'<! - METADATA TYPE =“typelib”FILE =“C:\ Program Files \ Common Files \ System \ ADO \ msado20.tlb” - - >'[使用METADATA导入DLL常量](http://www.4guysfromrolla.com/webtech/110199-1.shtml)而不是'global.asa'文件中的'adovbs.asp'来给出所有的ASP页面访问ADO常量。 ** 2。**您无法使用Request.Form的原因是因为您一旦调用Request,BinaryRead()'请求集合被无效,这就是为什么AspFreeUpload提供它自己的'Scripting.Dictionary'来访问这些值的原因。 – Lankymart