如果是Safari浏览器在iPhone上

Question

禁用您如何检测是否Safari浏览器已经在iPhone上的家长控制禁用如何检测？我知道这是可能的，因为App X3Watch拒绝工作，直到Safari被禁用。据我所见，家长控制没有api，那么可以使用哪种技术呢？

Answer 1

我没有测试过这一点，但OS3.0或更高版本，可以检测一个URL可以用[[UIApplication sharedApplication] canOpenURL:myURL]系统上的任何应用程序中打开。我敢打赌，如果Safari被禁用，它将返回NO。

Answer 2

这里是我的尝试包括在一个视图控制器解决这个。这两个布尔需要使用，因为用户可以在加载视图时独立于Safari浏览器打开外部程序，但需要Safari浏览器的按钮尚未打开。

@implementation ViewController { 
@private BOOL externalProgramOpened; 
@private BOOL buttonPressed; 
} 

-(void) setExternalProgramOpened { 
    // Only set to yes if we're trying to open safari 
    if(buttonPressed) { 
     externalProgramOpened = YES; 
    } 
} 

-(void) notifyUserOfRestrictedAccess { 

    if(externalProgramOpened == NO) { 
      [[[UIAlertView alloc] initWithTitle:@"Safari Needs to be enabled!" 
            message:@"It looks like the Safari browser is 
               disabled. Please enable it 
               (Settings>General>Restrictions) in order to 
               continue." 
            delegate:nil 
          cancelButtonTitle:@"Ok" 
          otherButtonTitles: nil] show]; 
    } else { 
     externalProgramOpened = NO; 
    } 

    buttonPressed = NO; 
} 

-(void) viewWillAppear:(BOOL)animated { 
    externalProgramOpened = NO; 
    buttonPressed = NO; 

    [[NSNotificationCenter defaultCenter] addObserver:self 
              selector:@selector(setExternalProgramOpened) 
              name:UIApplicationWillResignActiveNotification 
              object:nil]; 
} 

-(void) viewWillDisappear:(BOOL)animated { 

    [[NSNotificationCenter defaultCenter] removeObserver:self 
              name:UIApplicationWillResignActiveNotification 
              object:nil]; 
    [super viewWillDisappear:animated]; 

} 

- (IBAction)buttonPressed:(id)sender { 
    buttonPressed = YES; 

    NSString * URL = *someURL*; 

    [[UIApplication sharedApplication] openURL:[NSURL URLWithString:URL]]; 

    [self performSelector:@selector(notifyUserOfRestrictedAccess) withObject:self 
       afterDelay:.75]; 
}