我想显示表(Jquery DataTable
)的数据女巫我创建从JavaScript
但一些如何显示这样的表。jquery datatable显示没有可用的数据在表格后列表行数(javascript)
Jquery DataTable
正常显示,但如果我这样做搜索则显示通知No data available in table
就算我右键单击页面和View Page Source
新行不显示其功能甚至没有工作。 我不没有什么问题听我把初始化数据表的代码,
$(document).ready(function() {
$('#example').dataTable({
"sPaginationType" : "full_numbers"
});
});
在表中插入行代码
$("#example").find("tr:not(:first)").remove();
for (var i = 0; i < response.userListReturns.length; i++) {
var table = document.getElementById("example");
var thisRowCount = table.rows.length;
var row = table.insertRow(thisRowCount);
var cell1 = row.insertCell(0);
cell1.style.paddingTop = '4px';
cell1.style.paddingBottom = '4px';
cell1.style.textAlign = "center";
if(i%2!=0)
cell1.style.backgroundColor="#BAD6F7";
var element0 = document.createElement("input");
element0.type = "radio";
element0.id = "chkEditDelet"+i;
cell1.appendChild(element0);
var cell2 = row.insertCell(1);
cell2.style.paddingTop = '4px';
cell2.style.paddingBottom = '4px';
cell2.style.textAlign = "left";
if(i%2!=0)
cell2.style.backgroundColor="#BAD6F7";
cell2.innerHTML= i+1;
var cell3 = row.insertCell(2);
cell3.style.paddingTop = '4px';
cell3.style.paddingBottom = '4px';
cell3.style.textAlign = "left";
if(i%2!=0)
cell3.style.backgroundColor="#BAD6F7";//c4ffc4
cell3.style.whiteSpace="nowrap";
cell3.innerHTML= response.userListReturns[i].userName;
var cell4 = row.insertCell(3);
cell4.style.paddingTop = '4px';
cell4.style.paddingBottom = '4px';
cell4.style.textAlign = "left";
if(i%2!=0)
cell4.style.backgroundColor="#BAD6F7";//c4ffc4
cell4.innerHTML= response.userListReturns[i].userAddress;
var cell5 = row.insertCell(4);
cell5.style.paddingTop = '4px';
cell5.style.paddingBottom = '4px';
cell5.style.textAlign = "left";
if(i%2!=0)
cell5.style.backgroundColor="#BAD6F7";//c4ffc4
cell5.innerHTML= response.userListReturns[i].userPhoneNo;
var cell6 = row.insertCell(5);
cell6.style.paddingTop = '4px';
cell6.style.paddingBottom = '4px';
cell6.style.textAlign = "left";
if(i%2!=0)
cell6.style.backgroundColor="#BAD6F7";//c4ffc4
cell6.innerHTML= response.userListReturns[i].education;
var cell7 = row.insertCell(6);
cell7.style.paddingTop = '4px';
cell7.style.paddingBottom = '4px';
cell7.style.textAlign = "left";
if(i%2!=0)
cell7.style.backgroundColor="#BAD6F7";//c4ffc4
cell7.innerHTML= response.userListReturns[i].userLiginName;
var cell8 = row.insertCell(7);
cell8.style.paddingTop = '4px';
cell8.style.paddingBottom = '4px';
cell8.style.textAlign = "left";
if(i%2!=0)
cell8.style.backgroundColor="#BAD6F7";//c4ffc4
cell8.innerHTML= '********';
}
我尝试了很多其他的选择,但我认为这是我唯一的选择谢谢它的工作.. – Youddh