我的问题是,此函数返回的猜测是97和y的总和,而不是像switch语句指示的那样只是字母。奇怪的是,当我刚回来时,它的工作方式和我预期的完全一样。例如,当y = 4,并且返回y时,将显示4。当y = 4并且返回'guess'时,显示101。免责声明:这不是完整的代码。这真的很长,我认为是多余的,因为我唯一的问题是这个特定的函数返回'猜测',甚至不会返回y。如果所有的代码都可以使用,我会很乐意加以解决。C++ switch语句返回奇怪值
int letterguess(int z){
char guess;
int y;
y=letters[0][z];
switch (y){
case 0:
guess='a';
break;
case 1:
guess='b';
break;
case 2:
guess='c';
break;
case 3:
guess='d';
break;
case 4:
guess='e';
break;
case 5:
guess='f';
break;
case 6:
guess='g';
break;
case 7:
guess='h';
break;
case 8:
guess='i';
break;
case 9:
guess='j';
break;
case 10:
guess='k';
break;
case 11:
guess='l';
break;
case 12:
guess='m';
break;
case 13:
guess='n';
break;
case 14:
guess='o';
break;
case 15:
guess='p';
break;
case 16:
guess='q';
break;
case 17:
guess='r';
break;
case 18:
guess='s';
break;
case 19:
guess='t';
break;
case 20:
guess='u';
break;
case 21:
guess='v';
break;
case 22:
guess='w';
break;
case 23:
guess='y';
break;
case 24:
guess='y';
break;
case 25:
guess='z';
break;
}
return guess;
}
我真的不明白这可能会如何搞砸这样。提前致谢。
为什么从返回'int'的函数返回'char'? – Griwes
'guess = static_cast(y)+'a';'替换您的开关。 –
David
@Dave:的确,虽然技术上不可移植。 –