修改:提供物品的粗略路径。它不能知道变量的名字。
试试这个:
def iterate_nested(array_or_hash, depth = [], &block)
case array_or_hash
when Array:
array_or_hash.each_with_index do |item, key|
if item.class == Array || item.class == Hash
iterate_nested(item, depth + [key], &block)
else
block.call(key, item, depth + [key])
end
end
when Hash:
array_or_hash.each do |key, item|
if item.class == Array || item.class == Hash
iterate_nested(item, depth + [key], &block)
else
block.call(key, item, depth + [key])
end
end
end
end
应该重复,以必要的深度,由存储器等的限制,并返回返回项目的重点和项目和深度。适用于哈希和数组。
如果用测试:
iterate_nested([[[1,2,3], [1,2,3]], [[1,2,3], [1,2,3]], [[1,2,3], [1,2,3]]]) do |key, item, depth|
puts "Element: <#{depth.join('/')}/#{key}> = #{item}"
end
它产生:
Element: <0/0/0/0> = 1
Element: <0/0/1/1> = 2
Element: <0/0/2/2> = 3
Element: <0/1/0/0> = 1
Element: <0/1/1/1> = 2
Element: <0/1/2/2> = 3
Element: <1/0/0/0> = 1
Element: <1/0/1/1> = 2
Element: <1/0/2/2> = 3
Element: <1/1/0/0> = 1
Element: <1/1/1/1> = 2
Element: <1/1/2/2> = 3
Element: <2/0/0/0> = 1
Element: <2/0/1/1> = 2
Element: <2/0/2/2> = 3
Element: <2/1/0/0> = 1
Element: <2/1/1/1> = 2
Element: <2/1/2/2> = 3
Cheerio!
这是一个有趣的问题要回答,谢谢你的提问。 :-) – 2009-11-16 21:14:05