如何获取此对象中的值？

我一直在试图从下面的对象获得值没有任何运气。我知道那里有很多答案，但我是一个视觉人员，他们不适合我的布局。如何获取此对象中的值？

另外，如何处理对象以更改“ringAlarm”的值？

var strRingAlarm = { 
    sq1 :{ringAlarm:"OFF", alarmName:"Chime1"}, 
    sq2 :{ringAlarm:"NO", alarmName:"Chime2"}, 
    sq3 :{ringAlarm:"NO", alarmName:"Chime3"}, 
    sq4 :{ringAlarm:"NO", alarmName:"Chime4"}, 
    sq5 :{ringAlarm:"NO", alarmName:"Chime5"}, 
    sq6 :{ringAlarm:"NO", alarmName:"Chime6"}, 
    sq7 :{ringAlarm:"NO", alarmName:"Chime7"}, 
    sq8 :{ringAlarm:"NO", alarmName:"Chime8"}, 
    sq9 :{ringAlarm:"NO", alarmName:"Chime9"}, 
    sq10:{ringAlarm:"NO", alarmName:"Chime10"}, 
    sq11:{ringAlarm:"NO", alarmName:"Chime11"}, 
    sq12:{ringAlarm:"NO", alarmName:"Chime11"} 
}; 
     Object.getOwnPropertyNames(strRingAlarm).forEach(function(val, idx, array) { 
     console.log(val + ' -> ' + val.ringAlarm); 
} 
)

来源

2016-01-21 Dewinky

你可以得到ringAlarmProperty这样

for(var prop in strRingAlarm){ 
    console.log(strRingAlarm[prop].ringAlarm) 
}

来源

2016-01-21 19:08:51 Enjayy

var strRingAlarm = { 
    sq1: {ringAlarm:"OFF", alarmName:"Chime1"}, 
    sq2: {ringAlarm:"NO", alarmName:"Chime2"}, 
    sq3: {ringAlarm:"NO", alarmName:"Chime3"}, 
    sq4: {ringAlarm:"NO", alarmName:"Chime4"}, 
    sq5: {ringAlarm:"NO", alarmName:"Chime5"}, 
    sq6: {ringAlarm:"NO", alarmName:"Chime6"}, 
    sq7: {ringAlarm:"NO", alarmName:"Chime7"}, 
    sq8: {ringAlarm:"NO", alarmName:"Chime8"}, 
    sq9: {ringAlarm:"NO", alarmName:"Chime9"}, 
    sq10: {ringAlarm:"NO", alarmName:"Chime10"}, 
    sq11: {ringAlarm:"NO", alarmName:"Chime11"}, 
    sq12: {ringAlarm:"NO", alarmName:"Chime11"} 
}; 


Object.getOwnPropertyNames(strRingAlarm).forEach(function(val, idx, array) { 
    console.log(val + ' -> ' + strRingAlarm[val].ringAlarm) 
})

来源

2016-01-21 19:08:55 djaszczurowski

var strRingAlarm = { 
 
    sq1 :{ringAlarm:"OFF", alarmName:"Chime1"}, 
 
    sq2 :{ringAlarm:"NO", alarmName:"Chime2"}, 
 
    sq3 :{ringAlarm:"NO", alarmName:"Chime3"}, 
 
    sq4 :{ringAlarm:"NO", alarmName:"Chime4"}, 
 
    sq5 :{ringAlarm:"NO", alarmName:"Chime5"}, 
 
    sq6 :{ringAlarm:"NO", alarmName:"Chime6"}, 
 
    sq7 :{ringAlarm:"NO", alarmName:"Chime7"}, 
 
    sq8 :{ringAlarm:"NO", alarmName:"Chime8"}, 
 
    sq9 :{ringAlarm:"NO", alarmName:"Chime9"}, 
 
    sq10:{ringAlarm:"NO", alarmName:"Chime10"}, 
 
    sq11:{ringAlarm:"NO", alarmName:"Chime11"}, 
 
    sq12:{ringAlarm:"NO", alarmName:"Chime11"} 
 
}; 
 

 

 
for(key in strRingAlarm){ 
 
    console.log(key + "..." +strRingAlarm[key]['ringAlarm']) 
 
}

来源

2016-01-21 19:09:45 saikumar

为什么'ringAlarm'在'['ringAlarm']'而不是'.ringAlarm'中有什么特别的理由？ –

谢谢大家，非常感谢，这是踢我的azz！ – Dewinky

我们可以使用它们中的任何一个，我只是早点输入......就是这样 – saikumar

如果你有一个对象obj，以最好的方式的属性name得到该财产的价值是obj[name]。通过这种方式，试试这个代码块：

Object.getOwnPropertyNames(strRingAlarm).forEach(function(val, idx, array) { 
    console.log(val + ' -> ' + strRingAlarm[val].ringAlarm); 
});

Object.getOwnPropertyNames(strRingAlarm).forEach(function(val, idx, array) { 
    console.log(val + ' -> ' + strRingAlarm[val].ringAlarm); 
});

来源

2016-01-21 19:12:01 Cameron

如何获取此对象中的值？

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