如果排名总是相同，名称最上面的答案会得到+3，第二个+2，第三个+1和最后一个+0到它的关联actegory，你可以通过使用一些数据结构简化这个整个计算。 基本上，您只需要将每个可能的答案与一个类别相关联，然后将所有分数统计在一起。
最大的好处是，你可以再补充问题和类别不改变代码的其余部分。否则，如果添加一个类别，则必须为每个添加的问题重新编写整个if/else逻辑，并编辑所有已有的if/else。
就在这里展示的原则。应该更好地检查用户输入来扩展代码。并obv使用你自己的问题。等等
// Array with all used categories
var categories = [
'orientaal',
'houtig',
'bloemig',
'aromatisch',
'chypre',
'citrus'
],
// Array containing all the questions and the category of each answer
questions = [
{
'text' : 'Welk element spreekt jou het meest aan? Zet de letters van hoog naar laag (Bijv. DBAC).',
'answers' : {
'A' : {
'val' : 'Vuur',
'category' : 'orientaal'
},
'B' : {
'val' : 'Lucht',
'category' : 'bloemig'
},
'C' : {
'val' : 'Aarde',
'category' : 'houtig'
},
'D' : {
'val' : 'Water',
'category' : 'citrus'
}
}
}, {
'text' : 'Welk dier spreekt jou het meeste aan?',
'answers' : {
'A' : {
'val' : 'Draak',
'category' : 'orientaal'
},
'B' : {
'val' : 'Arend',
'category' : 'aromatisch'
},
'C' : {
'val' : 'Wolf',
'category' : 'houtig'
},
'D' : {
'val' : 'Slang',
'category' : 'chypre'
}
}
}, {
'text' : 'Welke locatie spreekt je het meeste aan?',
'answers' : {
'A' : {
'val' : 'Dennenbos',
'category' : 'houtig'
},
'B' : {
'val' : 'Steppe',
'category' : 'orientaal'
},
'C' : {
'val' : 'Oerwoud',
'category' : 'citrus'
},
'D' : {
'val' : 'Heide',
'category' : 'bloemig'
}
}
}
],
// Array to save the answers of the user.
userAnswers = [],
// Var to create the results.
scoreList;
// Let's 'fake' an interface that asks the questions. Replace this with your own form and functions that push the answers to the userAnswers array.
questions.forEach(function(questionObj, index) {
// Create the text for the possible answers from our questionObject.
var answerText = Object.keys(questionObj.answers).map(function(letter) {
// We just return the letter, plus a dot, plus the value corresponding with that letter.
return letter + '.: ' + questionObj.answers[ letter ].val;
}).join(', '),
// Ask the question, using the text inside our questionObj.
prompt = window.prompt('Vraag ' + (index + 1) + ': ' + questionObj.text + ' ' + answerText, '');
// Check if a 'valid' answer was entered. This should be expanded to also check that the input consists of some combination of ABCD
// if (prompt && prompt.length === 4) userAnswers.push(prompt);
// else alert('Gelieve alle 4 de letters in volgorde te zetten');
// But for now we'll just accept any answer for testing purposes.
userAnswers.push(prompt);
});
// Now let's check the score of the answers. We can reduce the users' answers into one value object that we can create by reducing our categories into a 'score list': A plain object with the category as the key adn the count as the value.
scoreList = userAnswers.reduce(function(scoreList, answer, index) {
// Since our answers are in the same order as our questions, we can just use the idnex to get the question associated with this answer.
var questionObj = questions[ index ],
// By splitting the answer, we get an array containing the 4 individual letters.
answerLetters = answer.split('');
// For each letter that is part of the answer, add the correct value to our score list.
answerLetters.forEach(function(letter, index) {
// The answered letter gives us the correct category
var category = questionObj.answers[ letter ].category;
// We can just use a static array to transform the index into the score: index 0 = score 3, i1 = s2, i2 = s1, i3 = s0
scoreList[ category ] += [ 3, 2, 1, 0 ][ index ];
});
return scoreList;
}, categories.reduce(function(scoreList, category) {
scoreList[ category ] = 0;
return scoreList;
}, {}));
// Report the results
alert(JSON.stringify(scoreList));
'if（q1.charAt（0）=='A'||'a'）'不会做你认为的事情。在if语句if（q1.charAt（1）=='A'|| q1.charAt（1）=='a'）中更改像这样（ –
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