异常处理的冒险III - 更新

Question

我有这样的Java代码骨架 -

 try { 
      Question q = null; //List of questions. I have put 3 in the list, in my main function 
      int i = 0; 
      while (i <= questions.size()) { 
       System.out.println("iteration " + i); 
       q = questions.get(i); 
       try { 
        try { 
         System.out.println("Script completed"); 
         break; 
        } catch (Exception e) { 
         // script is still executing... continue 
        } 
        //My entire logic is here.An exception is thrown in the first iteration 
        i++; 
       } catch (Exception e) { 
        //The thrown exception is caught here 
        try { 
        //The caught exception is handled here 
       } catch (IOException ioe) { 
        System.out.println("IO Exception.."); 
       } 
      } 
     } 
     } catch (IOException ioe) { 
      System.out.println("No more communication due to the lack of data"); 
     } catch (IllegalMonitorStateException imse) { 
      System.out.println("Illegal Monitor State Exception"); 
     } catch (IllegalThreadStateException itse) { 
      System.out.println("Illegal Thread State Exception"); 
     } 

---

而且输出我得到的是有点像这样 -

iteration 0 
//Exception handling related output 

iteration 0 //repeated because i++ doesn't happen since exception is thrown 
//Execution takes place normally 

iteration 1 
//???????? - Here is where i am facing the problem. I am not getting 

输出完全。我知道为什么我仍然在第1次迭代（这与i ++有关，因为第一次抛出异常而不会发生一次）。但任何人都可以帮助我如何成功执行此迭代呢？

Answer 1

您需要检查哪个catch块在每次迭代中被执行。如果在//try3或//try4（或者根本没有异常抛出）中引发异常，则执行i++将执行。

如果异常在//try2（无论是前//try3或后//catch4）抛出，然后i++不会执行。