比较两个表与通配符

Question

我需要比较两个表，其中一个有数据，另一个有解释。

所以数据表看起来像这样：

id | state | substate | stage | suppressed 
001 wip  A1   B3  Y 
003 wip  A1   B1  N 
005 done A2   B3  Y 
009 wip  A1   B3  N 
... and many more similar 

解释表具有以获得上面的4个状态（状态，子状态中，阶段，抑制），并将它们转换为人类可读：

state | substate | stage | suppressed | HRoutput1  | HRoutput2 
wip  A1  B1  N  "it's ok"  "wait...dont do anything" 
wip  A1  B3  N  "it's not ok" "better call saul" 
done  A2  B3  Y  "it's not ok" "forget about it" 
wip  A1  B1  Y  "it's ok"  "something minor needs to be done" 
*   *   *   Y  "it's ok"  "it's suppressed" 
done  *   *   *  "it's ok"  "it's being worked on" 

现在看到，在上述说明表具有2个阶段，其中i使用通配符在表

*,*,*,Y,"it's ok","its suppressed" 

当状态，子状态，阶段和抑制在上述任何标准中不匹配时应使用此项。

我做了什么直到现在，我装上的数据每行到一个数组A 然后让元件阵列通过解释表A中运行：

"SELECT * from explanation_table where state = '" . $data['state'] ."' and '" . $data['substate'] . "' ....etc etc 

然后运行查询和保存结果到一个解释阵列并打印结果

$data['id'] . $expl['HRoutput1'] . $expl['HRoutput2'] 

我的代码工作正常，除了通配符的情况。

Answer 1

要从查询简历，你可以这样做：

"SELECT * from explanation_table where (state = '" . $data['state'] ."' OR state = '*') and (substate = '" . $data['substate'] . "' OR substate = '*') ....etc etc.... ORDER BY state != '*', substate != '*' ... LIMIT 1 

这样一来，你会同时匹配通配符和准确状态/子状态/ ...匹配，valueing比通配符匹配更高的实际匹配（按顺序）并仅返回最佳匹配结果。