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运行我的应用程序时,LogCat中出现以下错误。 “未发现处理意图的活动”如何在清单中注册意向
按下button3,callButton时发生错误。这会尝试调出要联系的联系人列表。它什么都不做,并在几次按下后,应用程序崩溃。
我认为我必须将意图添加到清单中,但我不确定作为新手遇到了这个问题。
AndroidManifest
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.example.contactpicker" >
<uses-permission android:name="android.permission.READ_CONTACTS" />
<uses-permission android:name="android.permission.WRITE_CONTACTS" />
<uses-permission android:name="android.persmission.CALL_PHONE" />
<uses-sdk
android:minSdkVersion="14"
android:targetSdkVersion="18" />
<application android:icon="@drawable/ic_launcher" >
<activity
android:name="com.example.contactpicker.ContactPicker"
android:label="All Contacts" >
<intent-filter>
<action android:name="android.intent.action.PICK" >
</action>
<category android:name="android.intent.category.DEFAULT" >
</category>
<data
android:path="contacts"
android:scheme="content" >
</data>
</intent-filter>
</activity>
<activity
android:name="com.example.contactpicker.ContactPickerTester"
android:label="@string/title_activity_contact_picker_tester" >
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
<activity
android:name="com.example.contactpicker.ContactDetailActivity"
android:label="@string/title_activity_contact_detail" >
</activity>
<activity
android:name="com.example.contactpicker.ContactDetailFragment"
android:label="@string/title_activity_contact_detail_fragment" >
</activity>
<activity
android:name="com.example.contactpicker.ContactsListActivity"
android:label="@string/title_activity_contacts_list" >
</activity>
<activity
android:name="com.example.contactpicker.ContactsListFragment"
android:label="@string/title_activity_contacts_list_fragment" >
</activity>
<activity
android:name="com.example.contactpicker.ContentProviderActivity"
android:label="@string/title_activity_content_provider" >
</activity>
</application>
</manifest>
其他代码
public class ContactPickerTester extends Activity {
public static final int PICK_CONTACT = 1;
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_contact_picker_tester);
Button button = (Button) findViewById(R.id.button1);
button.setOnClickListener(new OnClickListener() {
public void onClick(View _view) {
Intent intent = new Intent(Intent.ACTION_PICK, Uri
.parse("content://contacts/"));
startActivityForResult(intent, PICK_CONTACT);
}
});
Button insertContactButton = (Button) findViewById(R.id.button2);
insertContactButton.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
insertContactWithIntent();
}
});
}
private void insertContactWithIntent() {
// inserting a new contact using intents//
Intent intent = new Intent(Intent.ACTION_INSERT,
ContactsContract.Contacts.CONTENT_URI);
startActivity(intent);
Button callButton = (Button) findViewById(R.id.button3);
callButton.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
Intent myIntent = new Intent(Intent.ACTION_DIAL, Uri.parse("content://contacts/"));
startActivity(myIntent);
}
});
}
@Override
public void onActivityResult(int reqCode, int resCode, Intent data) {
super.onActivityResult(reqCode, resCode, data);
switch (reqCode) {
case (PICK_CONTACT): {
if (resCode == Activity.RESULT_OK) {
Uri contactData = data.getData();
Cursor c = managedQuery(contactData, null, null, null, null);
c.moveToFirst();
String name = c
.getString(c
.getColumnIndexOrThrow(ContactsContract.Contacts.DISPLAY_NAME));
TextView tv = (TextView) findViewById(R.id.selected_contact_textview);
tv.setText(name);
}
break;
}
}
}
}
这个作品!但我想没有任何phoneNumber字符串,(我将它设置为0,并且当单击按钮时,它打开0上的拨号程序)。我怎样才能打开电话而不使用电话号码? – user3466400
如果您需要打开,请勿在意图中设置数据。另请参阅我的更新答案,如何启动联系人并根据需要选择号码 – Libin
谢谢! v有帮助 – user3466400