是否可以在Android中使用DOM解析器解析特定的XML？

以下格式是来自服务器的响应。我试图通过使用DOM解析这个，但得到异常说“只允许一个根元素”。是否可以在Android中使用DOM解析器解析特定的XML？

<?xml version="1.0" encoding="UTF-8" ?> 
    <responseCode>2000</responseCode> 
    <responseText>Success</responseText> 
    <response> 
    <response1>on</response1> 
    <response1>on</response1> 
    <response1>on</response1> 
    <response1>on</response1> 
    <response1>on</response1> 
    </response> 
    <response> 
    <response1>on</response1> 
    <response1>on</response1> 
    <response1>on</response1> 
    <response1>on</response1> 
    <response1>on</response1> 
    </response> 
    <response> 
    <response1>on</response1> 
    <response1>on</response1> 
    <response1>on</response1> 
    <response1>on</response1> 
    <response1>on</response1> 
    </response>

来源

2013-12-17 user3110163

yes.but你缺少一个根标签。也推荐使用xmlpullparser http://developer.android.com/training/basics/network-ops/xml.html – Raghunandan

@Raghunandan：嗨，感谢您的回复，如果您有示例代码，请发给我。 – user3110163

这将是使用XmlPullParser更容易解析，并更有效的太

例。 XML文件内容（保存在外部存储作为code.xml）

<?xml version="1.0" encoding="utf-8"?> 
<countries> 
<country> 
    <name>Iran</name> 
    <phonecode>+98</phonecode> 
    <code>IRI</code> 
</country> 
<country> 
    <name>United State</name> 
    <phonecode>+1</phonecode> 
    <code>USA</code> 
</country> 
</countries>

让我们开始分析它

首先创建一个辅助类

import android.util.Xml; 
import org.xmlpull.v1.XmlPullParser; 
import org.xmlpull.v1.XmlPullParserException; 
import java.io.IOException; 
import java.io.InputStream; 

public class XmlDataParseHelper { 

private XmlPullParser parser; 
private static final String NULL = null; 

/** 
* 
* @param in 
* @throws XmlPullParserException 
* @throws IOException 
* @throws IllegalArgumentException 
*/ 
public XmlDataParseHelper(InputStream in) throws XmlPullParserException, 
     IOException, IllegalArgumentException { 
    try { 
     parser = Xml.newPullParser(); 
     parser.setFeature(XmlPullParser.FEATURE_PROCESS_NAMESPACES, false); 
     parser.setInput(in, null); 
     parser.nextTag(); 
    } catch (Exception e) { 
     e.printStackTrace(); 
    } 
} 

/** 
* 
* @return XmlPullParser 
*/ 
public XmlPullParser getParser() { 
    return parser; 
} 

/** 
* 
* @param parser 
* @param tag 
* @return String 
* @throws IOException 
* @throws XmlPullParserException 
*/ 
public static String readTag(XmlPullParser parser, String tag) 
     throws IOException, XmlPullParserException { 
    String tagData = ""; 
    parser.require(XmlPullParser.START_TAG, NULL, tag); 
    if (parser.next() == XmlPullParser.TEXT) { 
     tagData = parser.getText(); 
     parser.nextTag(); 
    } 
    parser.require(XmlPullParser.END_TAG, NULL, tag); 
    return tagData; 
} 

/** 
* 
* @param parser 
* @param tag 
* @param attributeName 
* @return String 
* @throws IOException 
* @throws XmlPullParserException 
*/ 
public static String readAttribute(XmlPullParser parser, String tag, 
     String attributeName) throws IOException, XmlPullParserException { 
    parser.require(XmlPullParser.START_TAG, NULL, tag); 
    String attributeData = parser.getAttributeValue(NULL, attributeName); 
    parser.nextTag(); 
    parser.require(XmlPullParser.END_TAG, NULL, tag); 
    return attributeData; 
} 

}

读取XML文件as

public InputStream readFile(String fileName) throws FileNotFoundException, 
     IOException { 
//check external storage present 
// else throw new IOException(); 

return new FileInputStream(Environment.getExternalStorageDirectory() 
     + "/" + fileName); 
}

传递的InputStream它初始化XMLPullParser对象的另一种方法

public void readXmlFile(String fileName) { 
try { 
    if (fileName.isEmpty()) 
    throw new NullPointerException(); 
    readData(new XmlDataParseHelper(readFile(fileName)).getParser()); 
} catch (IOException e) { 
     e.printStackTrace(); 
} catch (XmlPullParserException e) { 
     e.printStackTrace(); 
} catch (IllegalArgumentException e) { 
     e.printStackTrace(); 
} 
}

Atlast解析XMLPullParser object作为

public void readData(XmlPullParser parser) 
      throws XmlPullParserException, IOException { 
int eventType = parser.getEventType(); 
String tagName = ""; 
Log.w("Developer", "Reading file..."); 
while (eventType != XmlPullParser.END_DOCUMENT) { 
    switch (eventType) { 
     case XmlPullParser.START_DOCUMENT : 
      Log.w("Developer", "Reading backup file..."); 
      break; 
     case XmlPullParser.START_TAG : 
      tagName = parser.getName(); 
      if (tagName.equals("countries")) { 
       Log.w("XMLParse", "Start TAG countries"); 
       // do something when countries tag starts 
      } 
      if (tagName.equals("country")) { 
       Log.w("XMLParse", "Start TAG country"); 
       // do some when country tag starts 
      } else if (tagName.equals("name")) { 
       // read tag value using XmlDataParseHelper class 
       String countryName = XmlDataParseHelper.readTag(parser, 
           "name"); 
       Log.w("XmlParser", "Country name : "+countryName); 
      } else if (tagName.equals("phonecode")) { 
       String countryPhoneCode = 
           XmlDataParseHelper.readTag(parser,"phonecode"); 
       Log.w("XmlParser", "Country Phone code : "+countryPhoneCode); 
      } else if (tagName.equals("code")) { 
       String countryCode = 
          XmlDataParseHelper.readTag(parser, "code"); 
       Log.w("XmlParser", "Country code name : "+countryCode); 
      } 
     break; 
     case XmlPullParser.END_TAG : 
      tagName = parser.getName(); 
      if (tagName.equals("countries")) { 
        // do something when counties tag is close. 
      }   
     break; 
    } 
    eventType = parser.next(); 
} 
Log.w("Developer", "File parsing complete..."); 
}

要读取文件只要调用方法readXmlFile(String fileName)在的AsyncTask的名称存储在外部存储器中的文件。

完整的Android工作示例代码是在这里https://gist.github.com/rachitrm/7810837或叉子项目http://www.github.com/rachitrm/rm-xmlparser/

来源

2013-12-17 07:59:48

嗨请看我的帖子一旦我的xml响应没有根元素是否可以使用xml解析器解析 – user3110163

@ user3110163是的，尝试上面的代码，就像XmlPullParser解析在开始文件和结束文件的基础上。下载该项目并尝试它...！我也在测试你的代码。 –

thnakyou洙很多我会尝试它 – user3110163

这是无效的XML。该反应应该是如下：

<root> 
    <responseCode>2000</responseCode> 
    <responseText>Success</responseText> 
    <response> 
    <response1>on</response1> 
    <response1>on</response1> 
    <response1>on</response1> 
    <response1>on</response1> 
    <response1>on</response1> 
    </response> 
    <response> 
    <response1>on</response1> 
    <response1>on</response1> 
    <response1>on</response1> 
    <response1>on</response1> 
    <response1>on</response1> 
    </response> 
    <response> 
    <response1>on</response1> 
    <response1>on</response1> 
    <response1>on</response1> 
    <response1>on</response1> 
    <response1>on</response1> 
    </response> 
</root>

来源

2013-12-17 07:38:48

谢谢你的回复是否有可能解析我的xml – user3110163

是否可以在Android中使用DOM解析器解析特定的XML？

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