2
AngularJS $scope.model
是不确定的,当我通过Javascript
<button ngf-select="upload($file)">Выбрать</button>
<span id="photoSpan"></span>
<input type="text" id="photo" name="uploadPhoto" ng-model="uploadPhoto">
这里初始化它是我的初始化代码:
document.getElementById("photo").value = fileName;
$("#photoSpan").text(resp.config.data.file.name);
console.log('Success ' + resp.config.data.file.name + 'uploaded. Response: ' + resp.data);
所以
createExpositionResource.photo = $scope.uploadPhoto;
console.log('--------------'+$scope.uploadPhoto);
回报undefined
。
我在做什么错?
谢谢!
好奇。谢谢!为我工作。 –