如何排除SQL中的周末？

Question

我在Orders表中有一个日期列SLA_Date。

我的SLA_Date应该排除周末（星期六&周日）。平日数据应单独显示。

如何在SQL中执行此操作？

Answer 1

你只需要添加以下过滤：

WHERE TO_CHAR(date_column, 'DY','NLS_DATE_LANGUAGE=AMERICAN') NOT IN ('SAT', 'SUN') 

您查询看起来像：

SELECT SLA_Date 
    FROM orders 
WHERE TO_CHAR(SLA_Date, 'DY','NLS_DATE_LANGUAGE=AMERICAN') NOT IN ('SAT', 'SUN') 

例如（WITH子句仅用于构建测试用例），下面的查询仅显示工作日（即，不包括周六和周日）从1st May 2015到31st May 2015：

SQL> WITH DATA AS 
    2 (SELECT to_date('05/01/2015', 'MM/DD/YYYY') date1, 
    3  to_date('05/31/2015', 'MM/DD/YYYY') date2 
    4 FROM dual 
    5 ) 
    6 SELECT date1+LEVEL-1 the_date, 
    7  TO_CHAR(date1+LEVEL-1, 'DY','NLS_DATE_LANGUAGE=AMERICAN') day 
    8 FROM DATA 
    9 WHERE TO_CHAR(date1+LEVEL-1, 'DY','NLS_DATE_LANGUAGE=AMERICAN') 
10  NOT IN ('SAT', 'SUN') 
11 CONNECT BY LEVEL <= date2-date1+1; 

THE_DATE DAY 
--------- --- 
01-MAY-15 FRI 
04-MAY-15 MON 
05-MAY-15 TUE 
06-MAY-15 WED 
07-MAY-15 THU 
08-MAY-15 FRI 
11-MAY-15 MON 
12-MAY-15 TUE 
13-MAY-15 WED 
14-MAY-15 THU 
15-MAY-15 FRI 
18-MAY-15 MON 
19-MAY-15 TUE 
20-MAY-15 WED 
21-MAY-15 THU 
22-MAY-15 FRI 
25-MAY-15 MON 
26-MAY-15 TUE 
27-MAY-15 WED 
28-MAY-15 THU 
29-MAY-15 FRI 

21 rows selected. 

SQL> 

有关详细示例，请参阅Generate Date, Month Name, Week Number, Day number between two dates

Answer 2

你可以试试下面的条件来过滤数据：

WHERE case to_char (SLA_Date, 'FmDay', 'nls_date_language=english') <> 'Saturday' 
    AND case to_char (SLA_Date, 'FmDay', 'nls_date_language=english') <> 'Sunday' 

Answer 3

select * 
from orders 
where TRUNC (thing) - TRUNC (thing, 'IW') between 0 and 4; 

http://sqlfiddle.com/#!4/db891/1