1
这是我的HTML:谷歌图表,PHP和Ajax
<script type="text/javascript" src="https://www.google.com/jsapi"></script>
<script type="text/javascript">
google.charts.load('current', {'packages':['corechart']});
google.charts.setOnLoadCallback(load_chart_data);
function load_chart_data() {
$.ajax({
url: "serv.php",
type: "POST",
dataType: "JSON",
data: {get_chart: true},
success: function(chart_values) {
draw_chart(chart_values);
}
});
}
function drawChart(chart_values) {
var data = google.visualization.arrayToDataTable(chart_values);
var options = {
title: 'Company Performance',
hAxis: {title: 'Year', titleTextStyle: {color: '#333'}},
vAxis: {minValue: 0}
};
var chart = new google.visualization.AreaChart(document.getElementById('chart2'));
chart.draw(data, options);
}
</script>
<div id="chart2"></div>
,这是我serv.php
<?php
if(isset($_POST['get_chart'])) {
$values = array(
array('Task', 'Hours Per Day'),
array('Work', 11),
array('Eat', 2),
array('Commute', 2),
array('Watch TV', 2),
array('Sleep', 7),
);
echo json_encode($values);
}
?>
此代码必须创建一个谷歌图,但什么是错的。请帮忙。而有趣的注意,JSON工作,并从serv.php数组已加载
尝试在PHP页面中添加页眉 '标题( '内容类型:应用程序/ JSON');' –
@ user1978142你能看看这个? – Oktu
我可以在哪里看? –