Numbers = [1, 2, 3, 4, 5]
x_list = list(itertools.combinations(Numbers, 2))
x_list = [(1, 2), (1, 3), (1, 4), (1, 5), (2, 3), (2, 4), (2, 5), (3, 4), (3, 5), (4, 5)]
现在，我想创建一个new_list，其中只包含1 [(1, 2), (1, 3), (1, 4), (1, 5)]。然后创建仅有两个奇数的new_list2，[(1, 3), (1, 5), (3, 5)]。Python 3.4.1 - 嵌套列表中的元素
我应该怎么办？提前致谢。
您可以使用过滤器拉姆达：
Numbers = [1, 2, 3, 4, 5]
x_list = list(combinations(Numbers, 2))
new_list1, new_list2 = list(filter(lambda x: 1 in x, x_list)) ,list(filter(lambda x: x[0] % 2 and x[1] % 2, x_list))
如有数模2具有余数，那么该数是奇数，x[0]是每个元组中第一个元素x[1]是第二个。
>>> new_list1，new_list2 = filter（lambda x：x [0] == 1，x_list），filter（lambda x：x [0]％2和x [1]％2，x_list）
>>> new_list1
<在0x00000000036754E0滤镜对象>
>>> new_list2
<滤镜对象在0x0000000003675588>
>>> –
2014-10-30 18:56:39
@MarkConcepcion，忘记你正在使用Python 3中，过滤器是在python迭代器3，从而需要调用'list（filter）' – 2014-10-30 19:02:28
您可以使用列表理解：
>>> [i for i in x_list if 1 in i] #contain_one
[(1, 2), (1, 3), (1, 4), (1, 5)]
>>> [(k,t) for k,t in x_list if k%2!=0 and t%2!=0] #odd_list
[(1, 3), (1, 5), (3, 5)]
In [2]: x_list = [(1, 2), (1, 3), (1, 4), (1, 5), (2, 3), (2, 4), (2, 5), (3, 4), (3, 5), (4, 5)]
In [3]: one_list = [c for c in x_list if c[0]==1]
In [4]: one_list
Out[4]: [(1, 2), (1, 3), (1, 4), (1, 5)]
In [5]: odd_list = [c for c in x_list if all(i%2==1 for i in c)]
In [6]: odd_list
Out[6]: [(1, 3), (1, 5), (3, 5)]
new_list = [a for a in x_list if 1 in a]
new_list2 = [a for a in x_list if a[0]%2!=0 and a[1]%2!=0]
这应该工作=）
您遇到过什么问题？ – 2014-10-30 17:42:21