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我对PHP相当陌生,但我有一个“API”设置在我的Web服务器上以发送/接收数据到MySQL数据库。
由于某种原因,当我向我的register.php文件(注册入口点)发送http post请求时,$_POST
变量保持为空。但是,在使用phpconfig()
并做了一些挖掘之后,我注意到我发送的参数存储在$_REQUEST
变量中,所以我相应地更改了我的register.php并且它工作正常。
我的问题是为什么发生这种情况,以及是否使用$_REQUEST
是错误的。
我用angularjs' $ HTTP发送HTTP请求:
var link = 'http://www.temporaryurl.com/register.php'
$http.post(link, {'name': 'Adam'},{'email': '[email protected]'},{'password': 'testingPass!'}).then(function(response) {
console.log("Http success!");
console.log(response);
}, function(response) {
console.log("Http failure");
console.log(response);
});
这里的register.php
<?php
require_once 'include/DB_Functions.php';
$db = new DB_Functions();
// json response array
$response = array("error" => FALSE);
if (isset($_REQUEST['name']) && isset($_REQUEST['email']) && isset($_REQUEST['password'])) {
// receiving the post params
$name = $_REQUEST['name'];
$email = $_REQUEST['email'];
$password = $_REQUEST['password'];
// Remove all illegal characters from email
$email = filter_var($email, FILTER_SANITIZE_EMAIL);
// Validate e-mail
if (!filter_var($email, FILTER_VALIDATE_EMAIL) === false) {
echo("$email is a valid email address");
} else {
echo("$email is not a valid email address");
}
if (!filter_var($email, FILTER_VALIDATE_EMAIL) === false) {
// check if user is already existed with the same email
if ($db->isUserExisted($email)) {
// user already existed
$response["error"] = TRUE;
$response["error_msg"] = "User already existed with " . $email;
echo json_encode($response);
} else {
// create a new user
$user = $db->storeUser($name, $email, $password);
if ($user) {
// user stored successfully
$response["error"] = FALSE;
$response["uid"] = $user["unique_id"];
$response["user"]["name"] = $user["name"];
$response["user"]["email"] = $user["email"];
$response["user"]["created_at"] = $user["created_at"];
$response["user"]["updated_at"] = $user["updated_at"];
echo json_encode($response);
} else {
// user failed to store
$response["error"] = TRUE;
$response["error_msg"] = "Unknown error occurred in registration!";
echo json_encode($response);
}
}
} else {
echo("$email is not a valid email address");
$response["error"] = TRUE;
$response["error_msg"] = "Email is invalid!";
echo json_encode($response);
}
} else {
$response["error"] = TRUE;
$response["error_msg"] = "Required parameters (name, email or password) is missing!";
echo json_encode($response);
}
?>
有一刻,我会更新我的帖子。 – awbasham
参考这篇文章http://stackoverflow.com/questions/15485354/angular-http-post-to-php-and-undefined并尝试。 – Perumal
'if(x === false)'是一个需要消除的反模式,只要使用'if(!x)'和'if(!x === false)'更加荒谬。这读作为三重否定:“如果不是字面上不假”。尽量避免像这样毫无意义的杂技。同样,我敢打赌,你的电子邮件“验证”表达式会拒绝许多绝对有效的地址,因为像'x @ google'这样的技术在技术上是有效的,尽管看起来可能有多荒谬。 – tadman