SQL - ORACLE改变行

Question

列

我有一些表

 
1 | 2 | test,test| 4 

我需要一个查询，以这种格式返回此表：

 
1 | 2 | test | 4 
1 | 2 | test | 4 

Answer 1

对不起，给你的链接。但是，可能会帮助你。

http://www.dba-oracle.com/t_converting_rows_columns.htm

http://asktom.oracle.com/pls/asktom/f?p=100:11:0::::P11_QUESTION_ID:419593546543

Answer 2

with src as 
(
     select '1' col0, '2' col1, 'test1,test2' col2 from dual union all 
     select '11' col0, '22' col1, 'test11,test22' col2 from dual 
) 
, explode as 
(
     select col0 
     ,  col1 
     ,  regexp_substr(col2, '\w+', 1, 1) as col2_1 
     ,  regexp_substr(col2, '\w+', 1, 2) as col2_2 
     --  if there is more add more... 
     from src 
) 
select col0, col1, col2_1 from explode where col2_1 is not null union all 
select col0, col1, col2_2 from explode where col2_2 is not null 
order by col0, col1, col2_1 
; 

1 2 test1 
1 2 test2 
11 22 test11 
11 22 test22 

五个值的示例：

with src as 
(
     select '1' col0, '2' col1, 'test1,test2'      col2 from dual union all 
     select '11' col0, '22' col1, 'test11,test22'      col2 from dual union all 
     select '111' col0, '222' col1, 'test31,test32,test33,test34,test35' col2 from dual 
) 
, explode as 
(
     select col0 
     ,  col1 
     ,  regexp_substr(col2, '\w+', 1, 1) as col2_1 
     ,  regexp_substr(col2, '\w+', 1, 2) as col2_2 
     ,  regexp_substr(col2, '\w+', 1, 3) as col2_3 
     ,  regexp_substr(col2, '\w+', 1, 4) as col2_4 
     ,  regexp_substr(col2, '\w+', 1, 5) as col2_5 
     --  if there is more add more... 
     from src 
) 
select col0, col1, col2_1, col2_2, col2_3, col2_4, col2_5 from explode where col2_1 is not null union all 
select col0, col1, col2_1, col2_2, col2_3, col2_4, col2_5 from explode where col2_2 is not null union all 
select col0, col1, col2_1, col2_2, col2_3, col2_4, col2_5 from explode where col2_3 is not null union all 
select col0, col1, col2_1, col2_2, col2_3, col2_4, col2_5 from explode where col2_4 is not null union all 
select col0, col1, col2_1, col2_2, col2_3, col2_4, col2_5 from explode where col2_5 is not null 
order by col0, col1, col2_1, col2_2, col2_3, col2_4, col2_4, col2_5 
; 

1 2 test1 test2   
1 2 test1 test2   
11 22 test11 test22   
11 22 test11 test22   
111 222 test31 test32 test33 test34 test35 
111 222 test31 test32 test33 test34 test35 
111 222 test31 test32 test33 test34 test35 
111 222 test31 test32 test33 test34 test35 
111 222 test31 test32 test33 test34 test35