检查对象中是否存在值

如何检查对象中是否存在邻域值？检查对象中是否存在值

{ 
    "results" : [ 
    { 
    "address_components" : [ 
     { 
      "long_name" : "2900", 
      "short_name" : "2900", 
      "types" : [ "street_number" ] 
     }, 
     { 
      "long_name" : "Ranch Road 620 North", 
      "short_name" : "Ranch Rd 620 N", 
      "types" : [ "route" ] 
     }, 
     { 
      "long_name" : "Villas On Travis", 
      "short_name" : "Villas On Travis", 
      "types" : [ "neighborhood", "political" ] 
     }, 
     { 
      "long_name" : "Austin", 
      "short_name" : "Austin", 
      "types" : [ "locality", "political" ] 
     }, 
     { 
      "long_name" : "Travis County", 
      "short_name" : "Travis County", 
      "types" : [ "administrative_area_level_2", "political" ] 
     }, 
     { 
      "long_name" : "Texas", 
      "short_name" : "TX", 
      "types" : [ "administrative_area_level_1", "political" ] 
     }, 
     { 
      "long_name" : "United States", 
      "short_name" : "US", 
      "types" : [ "country", "political" ] 
     }, 
     { 
      "long_name" : "78734", 
      "short_name" : "78734", 
      "types" : [ "postal_code" ] 
     }, 
     { 
      "long_name" : "2209", 
      "short_name" : "2209", 
      "types" : [ "postal_code_suffix" ] 
     } 
    ] 
    } 
] 
}

我已经试过

if ($jsonarray->results[0]->address_components[2]->types == 'neighborhood') { 
    $neighborhood = $jsonarray->results[0]->address_components[2]->long_name; 
}

来源

2017-01-10 santa

Anywhere的对象中的，或者在一个特定的地方？ –

类型仍然是一个数组，所以你不需要说类型[0] – Rob85

只有一个地方：https://maps.googleapis.com/maps/api/geocode/json?latlng=30.560030000000,-97.691430000000 – santa

它是一个数组：

if (in_array('neighborhood', $jsonarray->results[0]->address_components[2]->types)) { 
    $neighborhood = $jsonarray->results[0]->address_components[2]->long_name; 
}

因此，要检查他们，如果是那就是意图，如果只会有一个neighborhood：

foreach($jsonarray->results[0]->address_components as $array) { 
    if (in_array('neighborhood', $array->types)) { 
     $neighborhood = $array->long_name; 
     break; 
    } 
}

或者得到一个$neighborhood阵列中的所有的发现：

foreach($jsonarray->results[0]->address_components as $array) { 
    if (in_array('neighborhood', $array->types)) { 
     $neighborhood[] = $array->long_name; 
    } 
}

来源

2017-01-10 16:58:54 AbraCadaver

虽然在技术上并不正确，但我怀疑这是如此直接的方法。一些循环可能是为了... – deceze

是的，这是一个扩展的例子。 – AbraCadaver

if ($jsonarray->results[0]->address_components[2]->types[0] == 'neighborhood') { 
    $neighborhood = $jsonarray->results[0]->address_components[2]->long_name; 
}

来源

2017-01-10 17:00:47 Rob85

有没有任何保证，价值将永远在那个地方......？ – deceze

但基于他的代码，它在address_components [2]中的保证是什么，他正在寻找它，AbraCadavers的方式是更绝对的 – Rob85

检查对象中是否存在值

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