我有一个zip文件(大约10,000个小文件)的目录,每个文件都是一个CSV文件,我试图读取并分割成多个不同的CSV文件。从Zip文件中读取CSV
我设法编写代码以从CSV目录中拆分CSV文件,如下所示,它读取CSV的第一个atttribute,并且取决于将它写入相关的CSV。
import csv
import os
import sys
import re
import glob
reader = csv.reader(open("C:/Projects/test.csv", "rb"), delimiter=',', quotechar='"')
write10 = csv.writer(open('ouput10.csv', 'w'), delimiter=',', lineterminator='\n', quotechar='"', quoting=csv.QUOTE_NONNUMERIC)
write15 = csv.writer(open('ouput15.csv', 'w'), delimiter=',', lineterminator='\n', quotechar='"', quoting=csv.QUOTE_NONNUMERIC)
headings10=["RECORD_IDENTIFIER","CUSTODIAN_NAME","LOCAL_CUSTODIAN_NAME","PROCESS_DATE","VOLUME_NUMBER","ENTRY_DATE","TIME_STAMP","VERSION","FILE_TYPE"]
write10.writerow(headings10)
headings15=["RECORD_IDENTIFIER","CHANGE_TYPE","PRO_ORDER","USRN","STREET_DESCRIPTION","LOCALITY_NAME","TOWN_NAME","ADMINSTRATIVE_AREA","LANGUAGE"]
write15.writerow(headings15)
for row in reader:
type = row[0]
if "10" in type:
write10.writerow(row)
elif "15" in type:
write15.writerow(row)
因此,我现在试图读取Zip文件,而不是浪费时间先提取它们。
这就是我,因为我已经找到
import glob
import os
import csv
import zipfile
import StringIO
for name in glob.glob('C:/Projects/abase/*.zip'):
base = os.path.basename(name)
filename = os.path.splitext(base)[0]
datadirectory = 'C:/Projects/abase/'
dataFile = filename
archive = '.'.join([dataFile, 'zip'])
fullpath = ''.join([datadirectory, archive])
csv = '.'.join([dataFile, 'csv'])
filehandle = open(fullpath, 'rb')
zfile = zipfile.ZipFile(filehandle)
data = StringIO.StringIO(zfile.read(csv))
reader = csv.reader(data)
for row in reader:
print row
但是和错误被抛出
下尽可能多的教程后,至今AttributeError的:“海峡”对象有没有属性“读者”
希望有人可以告诉我如何更改我的CSV阅读代码,用于阅读Zip文件。
非常感谢
添
也许这是你如何粘贴代码,但几乎没有什么是你的名字循环。这个错误指的是什么? – 2012-02-18 18:27:47