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由于某些原因，当我在eclipse上运行我的代码时，屏幕上没有显示任何内容。我不确定它是什么。我可以在控制台中输入输入，但这是关于它的。没有其他事情发生谁能告诉我它可能是什么？谢谢。我的java代码没有错误，但它为什么不运行？
import java.util.Scanner;
public class Test {
public static void main (String [] args) {
Scanner input = new Scanner (System.in);
Flight flight = new Flight (input.nextLine(), input.nextLine(), input.nextLine(), input.nextLine(), 0);
System.out.println("Creating first flight");
System.out.println("What is the name of the flight?");
String flightName = input.nextLine();
System.out.println("What is the destination of the flight?");
String destination = input.nextLine();
System.out.println("What is the departure time of the flight?");
String departureTime = input.nextLine();
System.out.println("What is the departure gate of the flight?");
String departureGate = input.nextLine();
boolean done = false;
while (!done) {
System.out.println("Now what would you like to do?");
System.out.print("1. Print out a flight's info");
System.out.print("2. Print out the number of flights through the static variable.");
System.out.print("3. Change the departure time of a flight.");
System.out.print("4. Change the departure gate of a flight.");
System.out.print("5. Exit");
int choice = input.nextInt();
switch (choice) {
case 1:
System.out.println("Which flight would you like to print the info of (1 or 2)?");
int selection = 0;
selection = input.nextInt();
if (selection == 1 || selection == 2) {
Flight.printFlight();
} else{
System.out.println("Invalid Option");
} break;
case 2:
System.out.println("This is the number of flights" + Flight.getNumFlights());
break;
case 3:
System.out.println("Which flight would you like to change the departure time of (1 or 2)?");
int selection2 = 0;
selection2 = input.nextInt();
if (selection2 == 1 || selection2 == 2){
System.out.println("What is the new departure time for flight " + (Flight.getNumFlights()-1));
String newDeptTime = input.nextLine();
Flight.changeDeptTime(newDeptTime);
} else{
System.out.println("Invalid Option");
} break;
case 4:
System.out.println("Which flight would you like to change the departure gate of?");
int selection3 = input.nextInt();
if (selection3 == 1 || selection3 == 2){
System.out.println("What is the new departure gate for flight " + Flight.getNumFlights());
String newDeptGate = input.nextLine();
Flight.changeDeptGate(newDeptGate);
} else {
System.out.println("Invalid option");
} break;
case 5:
done = true;
break;
default:
System.out.println("Invalid option");
break;
}
}
}
}
放在一个断点，并在调试运行，并通过您的代码步，看看它打破用户。 – Araymer
即使在输入4行的'Flight'构造函数的参数后，您也没有获得输出，对吧？ – MikeCAT
由于您在构建Flight时请求使用Scanner在标准输入上输入内容，因此在您输入文本之前不会显示任何内容。 –