二进制列表到字符串列表 - Erlang

Question

如何将[<<"a">>, <<"b">>, <<"c">>]转换为["a", "b", "c"]？

Answer 1

[binary_to_list(X) || X <- [<<"a">>, <<"b">>, <<"c">>]].或更复杂的

 
BinList = [<<"a">>, <<"b">>, <<"c">>], 
NormalList = [binary_to_list(X) || X <- BinList], 
NormalList. 

Answer 2

，你可以做这样的：

A=[<<"a">>, <<"b">>, <<"c">>] 
B=[binary_to_list(Item) || Item <- A] 

Answer 3

或者，使用列表：映射/ 2：

lists:map(fun erlang:binary_to_list/1, [<<"a">>, <<"b">>, <<"c">>]).