我想读取/写入SQLite数据库,但我不断收到错误。我已经验证数据库存在... iPhone模拟器/应用程序/ 5.1 /应用程序#/ Documents/kipSQLDB.dbiOS SQLite插入并选择不工作?
我已经完成INSERT并从终端选择它。
但从应用程序它只是错误了。 (附加的问题 - 是否有使用SQLite一种方式来获得像MySQL的mysql_error信息的错误消息当我错误的应用程序,我什么也没得到,但是一些符号
这里是我的代码:
.H
?#import <Foundation/Foundation.h>
#import <sqlite3.h>
@interface SQLiteController : NSObject {
//file management
NSFileManager *fileManager;
NSString *documentsDirectory;
//sqlite data
sqlite3* databaseHandle;
}
- (void) initSQLiteDB;
- (void) insertData : (NSString*) fName : (NSString*) lName : (NSString*) companyName;
- (NSArray*) getData;
@end
.M
- (void) insertData : (NSString*) fName : (NSString*) lName : (NSString*) companyName {
NSString* insertStatement = [NSString stringWithFormat:@"INSERT INTO nameList (userFName, userLName, userCompany) VALUES (\"%@\", \"%@\", \"%@\")", fName, lName, companyName];
NSLog(@"%@", insertStatement);
char *error;
if (sqlite3_exec(databaseHandle, [insertStatement UTF8String], NULL, NULL, &error) == SQLITE_OK) {
int recordID = sqlite3_last_insert_rowid(databaseHandle);
NSLog(@"A record was inserted into the database %@ with the id of %i", databaseHandle, recordID);
} else {
NSLog(@"Error: %s", error);
}
}
- (NSArray*) getData {
NSMutableArray* dataArray = [[NSMutableArray alloc] init];
NSString* getStatement = @"SELECT * FROM nameList";
sqlite3_stmt *statement;
if (sqlite3_prepare_v2(databaseHandle, [getStatement UTF8String], -1, &statement, NULL) == SQLITE_OK){
// Iterate over all returned rows
while (sqlite3_step(statement) == SQLITE_ROW) {
int recordID = sqlite3_column_int(statement, 0);
NSString* fNameFromDB = [NSString stringWithUTF8String:(char*)sqlite3_column_text(statement, 1)];
NSLog(@"%@", fNameFromDB);
}
} else {
NSLog(@"No soup for you!");
}
return 0;
}
@end