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我们如何在symfony中编写内部连接查询?Symfony内部连接
$tagQuery = Doctrine_Query::create()
->from('SfTagging t')
->innerjoin('t.Link L ON t.taggable_id=L.id');
echo $tagQuery->getSqlQuery();
我们如何在symfony中编写内部连接查询?Symfony内部连接
$tagQuery = Doctrine_Query::create()
->from('SfTagging t')
->innerjoin('t.Link L ON t.taggable_id=L.id');
echo $tagQuery->getSqlQuery();
你并不需要指定ON部分,学说已经知道如何做,如果你的模式是不是太糟糕的加入。我会这样写:
$tagQuery = SfTaggingTable::getInstance()
->createQuery('t')
->innerJoin('t.Link');
echo $tagQuery->getSqlQuery();
$tagQuery = Doctrine_Query::create()
->from('SfTagging t')
->innerJoin('t.Link l');
echo $tagQuery->getSqlQuery();