将PowerShell输出重定向到.ps1

Question

我使用powershell来调用sql存储过程，现在我想将输出的完整集合重定向到.ps1文件中，因为输出行可在powershell中执行。

我试图使用> output.ps1，它的工作原理，但我检查输出文件，它包含很多'...'来替换实际输出。

如何导出完整的输出？还将标题关闭？

谢谢。

Answer 1

这取决于你如何调用存储过程。如果你在PowerShell中调用它，你应该能够收集输出，所以我假设你将它作为一个单独的任务开始它自己的窗口。没有你的实际例子，这里有一个从tasklist.exe命令收集输出的方法。你可能会发现它适用。

cls 
$exe = 'c:\Windows\System32\tasklist.exe' 
$processArgs = '/NH' 
try { 
    Write-Host ("Launching '$exe $processArgs'") 
    $info = New-Object System.Diagnostics.ProcessStartInfo 
    $info.UseShellExecute = $false 
    $info.RedirectStandardError = $true 
    $info.RedirectStandardOutput = $true 
    $info.RedirectStandardInput = $true 
    $info.WindowStyle = [System.Diagnostics.ProcessWindowStyle]::Hidden 
    $info.CreateNoWindow = $true 
    $info.ErrorDialog = $false 
    $info.WorkingDirectory = $workingDir 
    $info.Filename = $exe 
    $info.Arguments = $processArgs 

    $process = [System.Diagnostics.Process]::Start($info) 
    Write-Host ("Launched $($process.Id) at $(Get-Date)") 
    <# 
    $process.StandardOutput.ReadToEnd() is a synchronous read. You cannot sync read both output and error streams. 
    $process.BeginOutputReadLine() is an async read. You can do as many of these as you'd like. 
    Either way, you must finish reading before calling $process.WaitForExit() 
    http://msdn.microsoft.com/en-us/library/system.diagnostics.processstartinfo.redirectstandardoutput.aspx 
    #> 

    $output = $process.StandardOutput.ReadToEnd() 

    $process.WaitForExit() | Out-Null 

    Write-Host ("Exited at $(Get-Date)`n$output") 

} catch { 
    Write-Host ("Failed to launch '$exe $processArgs'") 
    Write-Host ("Failure due to $_") 
} 
$output