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我想优化下面的mysql查询。它运行约2.5秒。我已经阅读了复合索引,但我希望有人能够帮助我理解你如何将复合索引与这些包含多个联接的查询复合,其中许多条件(包括日期范围),一个组合以及一个order by一个计算值。我是否缺少有用的复合索引?有没有更有效的方法,我应该从这些表中提取数据?任何帮助非常感谢!复合索引顺序MySQL查询
SELECT
branch.name AS branch,
SUM(appointment.status = 'completed') AS `Completed`,
SUM(appointment.status = 'cancelled') AS `Cancelled`,
SUM(appointment.status = 'not completed') AS `Not Completed`,
SUM(appointment.status != 'rescheduled') AS `Total`
FROM rep
JOIN customer ON rep.id = customer.rep_id
JOIN office ON rep.office_id = office.id
JOIN appointment ON customer.id = appointment.customer_id
JOIN branch ON office.branch_id = branch.id
WHERE rep.active= 1
AND rep.group IN (1,2,3)
AND rep.deleted = 0
AND customer.saved = 0
AND (customer.rep_id != appointment.closed_by OR appointment.closed_by IS NULL)
AND customer.rep_id != 0
AND customer.deleted = 0
AND office.visible = 1
AND office.deleted = 0
AND appointment.date >= '2016-12-01'
AND appointment.date < '2017-11-30'
AND appointment.current = 1
GROUP BY branch.id
ORDER BY Completed
这里是EXPLAIN输出:
id: 1
select_type: simple
table: office
type: ref
possible_keys: PRIMARY, deleted_branchID_name, deleted_visible
key: deleted_visible
key_len: 5
ref: const,const
rows: 73
Extra: Using index condition; Using temporary; Using filesort
id: 1
select_type: simple
table: branch
type: eq_ref
possible_keys: PRIMARY
key: PRIMARY
key_len: 4
ref: office.branch_id
rows: 1
Extra: NULL
id: 1
select_type: simple
table: rep
type: ref
possible_keys: PRIMARY, group_id, office_id, active_deleted
key: office_id
key_len: 5
ref: office.id
rows: 57
Extra: Using index condition; Using where
id: 1
select_type: simple
table: customer
type: ref
possible_keys: PRIMARY, rep_id
key: rep_id
key_len: 4
ref: rep.id
rows: 61
Extra: Using where
id: 1
select_type: simple
table: appointment
type: ref
possible_keys: date, customer_id, closedByID_date, isCurrent_date
key: customer_id
key_len: 4
ref: customer.id
rows: 1
Extra: Using where
周围不知道你的数据进行任何删除无用的(),您的查询暗示索引'办公室(删除,可见,branch_id)'。然而,这张表似乎只包含少数几行,因此这个索引可能没有多大帮助;要选择更好的策略,您可以尝试识别强大的过滤器。如果例如99%的数据将具有'customer.saved = 1'或'appointment.current!= 1',您可以尝试使用它来优化您的查询 - 但这取决于您的数据。另外,为了清楚起见,你应该用'join'来替换除最后一个'left join'(如果'office.branch_id'为'not null',那么最后一个也是如此) – Solarflare