从URL到可绘制或位图的图像：最好和最快的方式

即时通讯尝试在我的应用程序中显示来自url的图像。但是我使用的方法很长。这个代码我建立在计算器在10-12秒加载从URL到可绘制或位图的图像：最好和最快的方式

public Bitmap getImage(String url,String src_name) throws java.net.MalformedURLException, java.io.IOException { 
      Bitmap bitmap; 
      HttpURLConnection connection = (HttpURLConnection)new URL(url) .openConnection(); 
      connection.setRequestProperty("User-agent","Mozilla/4.0"); 

      connection.connect(); 
      InputStream input= connection.getInputStream(); 

      bitmap = BitmapFactory.decodeStream(input); 

      return bitmap; 
}

10张图像。如果使用此代码。

和

///========================================================================================================================================== 
    public Drawable getImage(String url, String src_name) throws java.net.MalformedURLException, java.io.IOException 
     { 

     Drawable abc =Drawable.createFromStream(((java.io.InputStream)new java.net.URL(url).getContent()), src_name); 

      return abc; 


     }

如果使用此代码 - 图像中9-11秒加载。图像不大。最大宽度或高度是400-450。 ofcourse我告诉这个循环中的这个功能是这样的：for (int i =0;i<10;i++){image[i]=getImage(url);} 任何能告诉如何最好的和紧固显示图像在我的应用程序？问候，彼得。

来源

2011-08-08 Peter

你不能废除下载和解码图像所需的时间。数字'10'只是图像质量的函数，您只能尝试优化此数字。

如果服务器由您管理，您可能需要花一些时间根据您的UI要求优化可下载图像的大小。也请尝试延迟加载（我希望你不在UI线程上执行这些操作）。慵懒的下载和懒惰解码很多解决方案已经讨论过很多次：http://www.google.com.sg/search?q=android+images+lazy+load&ie=utf-8&oe=utf-8&aq=t&rls=org.mozilla:en-US:official&client=firefox-a

旁注：中HttpURLConnection的使用是不鼓励。使用HttpClient。这可能也会影响性能。看看http://lukencode.com/2010/04/27/calling-web-services-in-android-using-httpclient/

来源

2011-08-08 14:53:39

public static Bitmap getBitmapFromUrl(String url) { 
    Bitmap bitmap = null; 
    HttpGet httpRequest = null; 
    httpRequest = new HttpGet(url); 
    HttpClient httpclient = new DefaultHttpClient(); 

    HttpResponse response = null; 
    try { 
     response = (HttpResponse) httpclient.execute(httpRequest); 
    } catch (ClientProtocolException e) { 
     e.printStackTrace(); 
    } catch (IOException e) { 
     e.printStackTrace(); 
    } 

    if (response != null) { 
     HttpEntity entity = response.getEntity(); 
     BufferedHttpEntity bufHttpEntity = null; 
     try { 
      bufHttpEntity = new BufferedHttpEntity(entity); 
     } catch (IOException e) { 
      e.printStackTrace(); 
     } 

     InputStream instream = null; 
     try { 
      instream = bufHttpEntity.getContent(); 
     } catch (IOException e) { 
      e.printStackTrace(); 
     } 

     bitmap = BitmapFactory.decodeStream(instream); 
    } 
    return bitmap; 
}

来源

2012-05-10 15:36:09

public static Bitmap decodeFile(String filePath) { 
    // Decode image size 
    BitmapFactory.Options o = new BitmapFactory.Options(); 
    o.inJustDecodeBounds = true; 
    BitmapFactory.decodeFile(filePath, o); 

    // The new size we want to scale to 
    final int REQUIRED_SIZE = 1024; 

    // Find the correct scale value. It should be the power of 2. 
    int width_tmp = o.outWidth, height_tmp = o.outHeight; 
    int scale = 1; 
    while (true) { 
     if (width_tmp < REQUIRED_SIZE && height_tmp < REQUIRED_SIZE) 
      break; 
     width_tmp /= 2; 
     height_tmp /= 2; 
     scale *= 2; 
    } 

    // Decode with inSampleSize 
    BitmapFactory.Options o2 = new BitmapFactory.Options(); 
    o2.inSampleSize = scale; 
    Bitmap bitmap = BitmapFactory.decodeFile(filePath, o2); 
    return bitmap; 
}

来源

2012-05-10 15:41:45

从URL到可绘制或位图的图像：最好和最快的方式

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