查询具有鲜明和group by

Question

如何获得9300只出上表的？我只需要添加6500 + 1800 + 1000

这里是我当前的查询

SELECT 
SUM(e.amount)/(SELECT count(e2.receipt_no) 
       FROM entries e2 
       WHERE e2.receipt_no = e.receipt_no) as total, 
e.user_id 
FROM 
entries e 
GROUP BY e.receipt_no 

结果是

现在我需要得到每user_id

总

预期产量应为

Answer 1

从我的理解这应该给你想你想

SELECT sum(DISTINCT amount) as total, reciept_no FROM entries GROUP BY receipt_no

Answer 2

尝试这样

SELECT SUM(DISTINCT(amount)) as total, user_id FROM `entries` GROUP BY user_id 

Answer 3

一些东西试试这个

SELECT SUM(amount) as total,user_id FROM entries GROUP BY user_id 

Answer 4

首先计算DISTINCT量按用户组重新分组ceipt_no然后USER_ID有条目组的总和：

SELECT sum(total),userid from (SELECT sum(DISTINCT amount) as total, 
userid,receipt_no FROM entries GROUP BY userid,receipt_no) as rgrouped 
GROUP BY userid 

Answer 5

你也可以试试这个

SELECT user_id, SUM(DISTINCT `amount`) FROM `test` group by `user_id` 

第1步：为每个用户ID选择不同的量

101 - 6500,1800,1000 
189 - 1019.00 

步骤 - 2

101 = 6500+1800+1000 = 9300.00 
189 = 1019.00 

T他将为每个用户ID选择distinct金额，然后添加选定的金额并给出相同的结果。