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最近有一个类似的问题,但仍然无法得到它。我必须在添加新用户之前验证注册页面。NodeJS - 如何打破功能?
app.post('/signup', function(req, res) {
//checking if first name is filled
if (req.body.first_name = "" || req.body.first_name = null || req.body.first_name = undefined) {
res.render('signup', { "title": "Ttitle", "menu": "signup", user: req.user, "error" : "empty_first_name" });
break;
}
//checking if last name is filled
if (req.body.last_name = "" || req.body.last_name = null || req.body.last_name = undefined) {
res.render('signup', { "title": "Ttitle", "menu": "signup", user: req.user, "error" : "empty_last_name" });
break;
}
//checking if email is filled
if (req.body.email = "" || req.body.email = null || req.body.email = undefined) {
res.render('signup', { "title": "Ttitle", "menu": "signup", user: req.user, "error" : "empty_email" });
break;
}
//checking if passwords match
if (req.body.password != req.body.repassword) {
res.render('signup', { "title": "Ttitle", "menu": "signup", user: req.user, "error" : "pass_missmatch" });
break;
}
...
...
...
//and finally if everything seems to be OK...
addUser(req.body.email, req.body.password, req.body.first_name, req.body.last_name, req.body.country, function(status) {
res.render('signup', { "title": "Ttitle", "menu": "signup", user: req.user, "success" : 1 });
});
});
Node.JS告诉我所有的休息都是非法的。但是,我应该如何以适当的方式打破我的功能?它不会返回任何东西。谢谢!
你的意思是像水木清华返回NULL? – f1nn
@IlyaRusanen:只是'回来;'应该做的伎俩。没有要求提供明确的返回值。 –
它的工作,谢谢! – f1nn