2013-10-09 32 views
0

在PHP选择从MySQL数据库填充填充下拉菜单如何获得价值?

//function for dropdown 

function getDropDown($name, $table, $code, $desc) 
{ 
    $query = "SELECT $code, $desc FROM $table"; 
    echo "<select name=\"$name\">"; 
    echo '<option> Select One </option>'; 
    connect(); //connects to mysql 
    $result = mysql_query($query);`enter code here` 
    if(!$result) die ("error" . mysql_error()); 
    $foundRows = mysql_numrows ($result); 
    //loop to populate dropdown 
    for($row = 0; $row < $foundRows; ++$row) 
    { 
    list($c, $d) = mysql_fetch_row($result); 
    echo "<option name= value=\"$c\">$d</option>"; 
    } 
    echo "</select>"; 
} 

要使用选择如何获得价值?

+0

请澄清...你是什么意思的“得到价值,如果sekected”?你是否想在表单提交之后设置'