蟒蛇分裂

Question

我有以下字符串：

（一些文本）或（（其它文本）和（一些文字））和（仍更多的文字）

我想一个python正则表达式，将其分解成

['(some text)', '((other text) and (some more text))', '(still more text)'] 

我已经试过，但它不工作：

haystack = "(some text) or ((other text) and (some more text)) and (still more text)" 
re.split('(or|and)(?![^(]*.\))', haystack) # no worky 

任何帮助表示赞赏。

Answer 1

我会用re.findall代替re.split。而且注意，这只会工作高达深度的括号2

>>> import re 
>>> s = '(some text) or ((other text) and (some more text)) and (still more text)' 
>>> re.findall(r'\((?:\((?:\([^()]*\)|[^()]*)*\)|[^()])*\)', s) 
['(some text)', '((other text) and (some more text))', '(still more text)'] 
>>> 

Answer 2

你可以试试这个 re.split（ '[A-F] +'， '0a3B9'，旗帜= re.IGNORECASE）

Answer 3

该解决方案适用于任意嵌套的括号，其中一个正则表达式不能（s是原始字符串）：

from pyparsing import nestedExpr 
def lst_to_parens(elt): 
    if isinstance(elt,list): 
     return '(' + ' '.join(lst_to_parens(e) for e in elt) + ')' 
    else: 
     return elt 

split = nestedExpr('(',')').parseString('(' + s + ')').asList() 
split_lists = [elt for elt in split[0] if isinstance(elt,list)] 
print ([lst_to_parens(elt) for elt in split_lists]) 

输出：

['(some text)', '((other text) and (some more text))', '(still more text)'] 

对于OP真实的测试案例：

s = "(substringof('needle',name)) or ((role eq 'needle') and (substringof('needle',email))) or (job eq 'needle') or (office eq 'needle')" 

输出：

["(substringof ('needle' ,name))", "((role eq 'needle') and (substringof ('needle' ,email)))", "(job eq 'needle')", "(office eq 'needle')"] 

Answer 4

您还可以检查此

import re 
s = '(some text) or ((other text) and (some more text)) and (still more text)' 
find_string = re.findall(r'[(]{2}[a-z\s()]*[)]{2}|[(][a-z\s]*[)]', s) 
print(find_string) 

输出：

['(some text)', '((other text) and (some more text))', '(still more text)'] 

编辑

find_string = re.findall(r'[(\s]{2}[a-z\s()]*[)\s]{2}|[(][a-z\s]*[)]', s)