Laravel雄辩：多选和where子句查询

Question

我试图让从我的销售表吐出这样的查询：

For each `Brand`  
    `Brand` { 
     this month `sum(quantity)` 
     this month last year `sum(quantity)` 
     this year `sum(quantity)` 
     this last year `sum(quantity)` 
     `Brand` name 
    } 
    Next `Brand` { 
     this month `sum(quantity)` 
     this month last year `sum(quantity)` 
     this year `sum(quantity)` 
     this last year `sum(quantity)` 
     `Brand` name 
    } 

我有这个，但它不是吐出任何东西。如果我删除wheres它会得到这些款项不在我需要的日期范围内，所以我知道它的问题。我不确定是否可以做多个小麦

public function sales() 
    { 

     return $this->hasMany('App\Sale', 'account_vip_id', 'vip_id') 
            ->select('brand', DB::raw('sum(quantity) as month'))->whereMonth('date','=',date('m')) 
            ->addSelect('brand', DB::raw('sum(quantity) as month_last'))->whereDate('date','=',date('m Y',strtotime("-1 year"))) 
            ->addSelect('brand', DB::raw('sum(quantity) as year'))->whereYear('date','=',date('Y')) 
            ->addSelect('brand', DB::raw('sum(quantity) as year_last'))->whereYear('date','=', date("Y",strtotime("-1 year"))) 
            ->groupBy('brand'); 

    } 

Answer 1

不幸的是，SQL不能这样工作。您需要将where子句放入sum函数中。我创建了一个快速查询，让您更好地了解我在说什么...

SELECT 
    brands.name, 
    SUM(IF(DATE_FORMAT(NOW(), '%y-%m') = DATE_FORMAT(sales.created_at, '%y-%m'), sales.quantity, 0)) AS `month`, 
    SUM(IF(DATE_FORMAT(DATE_SUB(NOW(), INTERVAL 1 MONTH), '%y-%m') = DATE_FORMAT(sales.created_at, '%y-%m'), sales.quantity, 0)) AS `last_month`, 
    SUM(IF(YEAR(CURDATE()) = YEAR(sales.created_at), sales.quantity, 0)) AS `year`, 
    SUM(IF(YEAR(CURDATE()) - 1 = YEAR(sales.created_at), sales.quantity, 0)) AS `last_year` 
FROM brands 
INNER JOIN sales ON brands.id = sales.brand_id 
GROUP BY brands.name;