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我正在使用Express构建Web应用程序。我想合并,缩小和服务.js文件。我写了一个中间件,这是我的代码:使用Express合并,缩小和提供JavaScript文件,但不会缩小响应
var fs = require('fs'),
path = require('path'),
uglify = require('uglify-js'),
cache = '',
scriptsDir = path.join(__dirname, '../scripts'),
files = fs.readdirSync(scriptsDir);
// Sync read is not a problem since the following code is executed on startup
files.forEach(function(fname) {
if (/^.*\.js$/.test(fname)) {
cache += fs.readFileSync(path.join(scriptsDir, fname), 'utf8').toString();
}
});
cache = uglify.minify(cache, { fromString: true }).code;
module.exports = function(req, res, next) {
if (req.url === '/js/all.js')
res.end(cache);
else
next();
};
中间件是这样使用:
app.use(compress());
[...]
app.use(app.router);
app.use(jsMerger); // Here is my middleware
app.use(express.static(path.join(__dirname, '../public')));
的问题是不gzip压缩响应。此外,响应中还有“无标题”(我的意思是,没有缓存标题,没有etags; static
中间件提供的其他资源具有这些标题)。这是回应:
X-Powered-By: Express
Transfer-Encoding: chunked
Date: Wed, 12 Mar 2014 14:04:19 GMT
Connection: keep-alive
我错过了什么吗?如何压缩响应?
有关进一步参考,uglify = require('uglify-js')行会导入uglify.js2库(https://github.com/mishoo/UglifyJS2) – mneri