JsonMappingException无法反序列化java.lang.Integer中

我想在我的数据库中插入对象的实例，但我得到这个错误JsonMappingException无法反序列化java.lang.Integer中

Failed to read HTTP message: org.springframework.http.converter.HttpMessageNotReadableException: Could not read document: Can not deserialize instance of java.lang.Integer out of VALUE_TRUE token 
at [Source: [email protected]; line: 1, column: 353] (through reference chain: com.example.beans.Domain["isActive"]); nested exception is com.fasterxml.jackson.databind.JsonMappingException: Can not deserialize instance of java.lang.Integer out of VALUE_TRUE token 
at [Source: [email protected]; line: 1, column: 353] (through reference chain: com.example.beans.Domain["isActive"])

我的代码是：

@Entity 
public class Domain implements Serializable{ 

    @Id 
    @GeneratedValue(strategy=GenerationType.IDENTITY) 
    private Integer id; 
    ... 
    private Integer isActive; 

    public Integer getIs_active() { 
     return isActive; 
    } 
    public void setIs_active(Integer is_active) { 
     this.isActive = is_active; 
    }

来源

2016-10-04 Elgallati Noreddine

Integar是标量，试图让“字符串” json的值。检查这个线程https://github.com/FasterXML/jackson-dataformat-xml/issues/139 –

我相信你isActive的JSON是布尔值isActive : true 它期望的布尔类型不是整数。这是使你的杰克逊

更改isActive您private Integer isActive;到private boolean isActive;

来源

2016-10-04 09:01:49 mhasan

谢谢，它解决了这个问题 –

你的getter和setter方法应该是getIsActive和setIsActive，没有下划线

public Integer getIsActive() { 
     return isActive; 
} 

public void setIsActive(Integer is_active) { 
     this.isActive = is_active; 
}

来源

2016-10-04 09:04:29

JsonMappingException无法反序列化java.lang.Integer中

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