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嗨 我在QT 4.6.2中实现了一个简单的线程化GUI应用程序。我正在使用QThread没有继承它。我在start()函数中调用了usleep()函数,但这会导致GUI冻结。我如何解决这个问题。下面是代码qthread块中的睡眠呼叫块UI线程
#ifndef ECGREADER_H
#define ECGREADER_H
#include<QObject>
class ecgreader : public QObject
{
Q_OBJECT
public:
ecgreader(QObject *parent=0);
~ecgreader();
public Q_SLOTS:
void start();
Q_SIGNALS:
void finished();
};
#endif // ECGREADER_H
下面是start()函数
void ecgreader::start()
{
int i= system("ls>output.txt");
SLEEP(10000);
if(i==0)
{
emit finished();
}
}
终于开始呼叫这里
void Application::onbtnclicked()
{
QThread* thread=new QThread;
ecgreader* reader=new ecgreader;
reader->moveToThread(thread);
connect(thread,SIGNAL(started()),reader,SLOT(start()));
connect(reader,SIGNAL(finished()),thread,SLOT(quit()));
connect(reader,SIGNAL(finished()),reader,SLOT(deleteLater()));
connect(reader,SIGNAL(finished()),thread,SLOT(deleteLater()));
reader->start();
}
取得请帮