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您好专家我在SQL Server的更新查询中遇到问题。首先运行select查询,然后将结果传递给currentdb.execute(用于更新当前正在使用的访问文件的表),使用Access vba我不正确。我真的希望你能帮助我。也许你们知道更好的方式来运行我的程序:错误:访问SQL Server的VBA查询
- 连接到sql server 2008,运行select查询。
- 将选择查询的结果传递给访问数据库执行命令(或者如果您有更好的想法)更新当前正在使用的访问文件中的表。
我得到的代码错误是类型不匹配,并突出显示.OpenSchema。
这些是我犯错的代码的一部分(我真的不知道如何做到这一点)。
dbObj.Execute ("UPDATE ACCESS.tbl_Name RIGHT JOIN " & _
conn.OpenSchema(adSchemaTables, Array(Empty, Empty, Empty, "SQLSVR.tbl_Name")) & _
" ON ACCESS.tbl_Name.FieldName_access = " & rst!FieldName_sqlsvr & _
" SET ACCESS.tbl_Name.FieldName_access = " & rst!FieldName_sqlsvr)
这些是整个代码。
Option Compare Database
Sub LocalSQLServerConn_Test()
Dim dbOjb As DAO.Database
Dim strDBName As String
Dim strUserName As String
Dim strPassword As String
Set dbObj = CurrentDb()
Set conn = New adodb.Connection
Set rst = New adodb.Recordset
strDBName = "DataSet"
strConnectString = "Provider = SQLOLEDB.1; Integrated Security = SSPI; " & _
"Initial Catalog = " & strDBName & "; Persist Security Info = True; " & _
"Workstation ID = ABCDE12345;"
conn.ConnectionString = strConnectString
conn.Open
strSQL = "SELECT DISTINCT SQLSVR.tbl_Name.FieldName_sqlsvr FROM SQLSVR.tbl_Name"
rst.Open Source:=strSQL, ActiveConnection:=conn, _
CursorType:=adOpenDynamic, LockType:=adLockOptimistic
If rst.RecordCount = 0 Then
MsgBox "No records returned"
Else
rst.MoveFirst
Do While Not rst.EOF
dbObj.Execute ("UPDATE ACCESS.tbl_Name RIGHT JOIN " & _
conn.OpenSchema(adSchemaTables, Array(Empty, Empty, Empty, "SQLSVR.tbl_Name")) & _
" ON ACCESS.tbl_Name.FieldName_access = " & rst!FieldName_sqlsvr & _
" SET ACCESS.tbl_Name.FieldName_access = " & rst!FieldName_sqlsvr)
rst.MoveNext
Loop
End If
conn.Close
rst.Close
Set dbObj = Nothing
末次
如果你只是想更新ACCESS.tbl_Name,难道你不完全放弃RIGHT JOIN并有“UPDATE ... SET ...”吗? (我不是这方面的专家。) – Richard