我有一个表activity_types,其中包含活动的文本,例如
New project has been assigned to {user} with name {project}
New discussion has been posted by {client} on {project}
Project {project} has been closed by {user}
A draft has been approved by {client} on {project}
等Mysql替换函数返回null
我对这些文本的ID已被填充另一个表。
现在,我的要求是内{}与像{}客户应与客户名称所取代他们的实际值,(项目)应与项目名称替换替换文本来获取这些。
我已经使用嵌套取代MySQL的函数尝试,但它返回空字符串。这里是我的查询
SELECT REPLACE(REPLACE(REPLACE(att.type_text, '{project}', p.project_business_name), '{user}', u.user_fullname), '{client}', c.client_name) AS activity, a.*
FROM activities a
LEFT JOIN activity_types AS att ON att.type_id = a.activity_type
LEFT JOIN users u ON u.user_id = a.activity_user AND a.activity_user IS NOT NULL
LEFT JOIN projects p ON p.project_id = a.activity_project AND p.project_is_removed = '0'
LEFT JOIN clients c ON c.client_id = a.activity_client AND a.activity_client IS NOT NULL;
的问题是,如果我取代静态文本的c.client_name它工作正常,但是当我更换c.client_name静态字符串时,它在没有活动{客户端返回null }。任何猜测我在哪里做错了?
完美...日Thnx :) –
欢迎您@ShayanHusaini! –