PHP MYSQL错误处理 - 预处理语句

Question

我想实现安全查询使用预处理语句：

if (!($stmt = $db->prepare($q['query1']))) { 
    myException("Prepare failed: (" . $db->errno . ") " . $db->error); 
} else if (!$stmt->bind_param("si", $variable1, $variable2)) { 
    myException("Binding parameters failed: (" . $stmt->errno . ") " . $stmt->error); 
} else if (!$stmt->execute() || !$stmt->store_result()) { 
    myException("Execute failed: (" . $stmt->errno . ") " . $stmt->error); 
} else { 
(...) 

是它最好的方式做到这一点？此代码不可读。我可以使用类似尝试捕获块而不是if/else if？它会运作良好吗？

Answer 1

，你想，这将是更清楚：

try { 
    $stmt = $db->prepare($q['query1']); 

    $stmt->bind_param("si", $variable1, $variable2); 
    $stmt->bind_param("is", $variable3, $variable4); 

    if($stmt->execute()) { 
     $stmt->store_result(); 
     $stmt->bind_result($result); 
     $stmt->close(); 
    } else { 
     throw new Exception("error"); 
    } 
} catch (\Exception $e) { 
    echo $e->getMessage(); 
} 

[代码已经因编辑以OP请求]

Answer 2

try { 
    $stmt = $db->prepare($q['query']); 
    $stmt->bind_param("s", $s); 
    $stmt->execute(); 
    $stmt->store_result(); 
    $stmt->bind_result($result); 

    if ($stmt->fetch()) { 
     $stmt->close(); 
     return $result; 
    } 
    else 
     throw new Exception("error"); 
} catch (Exception $e) { 
    myExceptionHandler($e); 
} 

你愿意接受这个代码吗？ :)