每个人都应该有一个好的分离器。有很多选项可用。然而,我确实提供了我使用的那个。
下面列出两个选项,第一个是内嵌版本,第二个使用解析函数。两者都会返回相同的结果。
选项1 - 如果没有一个解析函数
Declare @MonthNoCsv varchar(50) = '2,3,4'
;with cte as (
Select RetSeq = Row_Number() over (Order By (Select null))
,RetVal = LTrim(RTrim(B.i.value('(./text())[1]', 'varchar(max)')))
From (Select x = Cast('<x>' + replace((Select replace(@MonthNoCsv,',','§§Split§§') as [*] For XML Path('')),'§§Split§§','</x><x>')+'</x>' as xml).query('.')) as A
Cross Apply x.nodes('x') AS B(i)
)
Select U.*
from cte M
Join Bookings B on M.RetVal=B.MonthNo and B.IsPaid=1
Join Users U on U.UserID=B.UserID
Group By U.UserID,U.Name
Having Count(Distinct B.MonthNo)=(Select max(RetSeq) from cte)
选项2 - 对于parse函数
Declare @MonthNoCsv varchar(50) = '2,3,4'
;with cte as (
Select * from [dbo].[udf-Str-Parse](@MonthNoCsv,',')
)
Select U.*
from cte M
Join Bookings B on M.RetVal=B.MonthNo and B.IsPaid=1
Join Users U on U.UserID=B.UserID
Group By U.UserID,U.Name
Having Count(Distinct B.MonthNo)=(Select max(RetSeq) from cte)
都返回
UserID Name
2 Bill
的UDF如果有兴趣
CREATE FUNCTION [dbo].[udf-Str-Parse] (@String varchar(max),@Delimiter varchar(10))
Returns Table
As
Return (
Select RetSeq = Row_Number() over (Order By (Select null))
,RetVal = LTrim(RTrim(B.i.value('(./text())[1]', 'varchar(max)')))
From (Select x = Cast('<x>' + replace((Select replace(@String,@Delimiter,'§§Split§§') as [*] For XML Path('')),'§§Split§§','</x><x>')+'</x>' as xml).query('.')) as A
Cross Apply x.nodes('x') AS B(i)
);
--Thanks Shnugo for making this XML safe
--Select * from [dbo].[udf-Str-Parse]('Dog,Cat,House,Car',',')
--Select * from [dbo].[udf-Str-Parse]('John Cappelletti was here',' ')
--Select * from [dbo].[udf-Str-Parse]('this,is,<test>,for,< & >',',')
此链接http://www.sommarskog.se/arrays-in-sql-2008.html可能让你开始 - 但我怀疑它需要技巧的水平超出了你的实施能力。在http://www.sommarskog.se/arrays-in-sql.html – SMor