我有两个问题:对象引用不设置到对象asp.net的实例,
- 我如何可以使用其他方式的文本框,以便它不会引发任何错误?
- 我得到了一个错误:未设置为一个对象的实例
“对象引用
,我不知道如何解决它 请能有人拿。一看?
protected void DataGridView1_RowCommand(object sender, GridViewCommandEventArgs e)
{
if (e.CommandName.Equals("InsertFooter"))
{
try
{
System.Web.UI.WebControls.TextBox txtEmp_num = (System.Web.UI.WebControls.TextBox)DataGridView1.Controls[0].Controls[0].FindControl("txtEmp_num");
System.Web.UI.WebControls.TextBox txtEmp_fn = (System.Web.UI.WebControls.TextBox)DataGridView1.Controls[0].Controls[0].FindControl("txtEmp_fn");
System.Web.UI.WebControls.TextBox txtEmp_ln = (System.Web.UI.WebControls.TextBox)DataGridView1.Controls[0].Controls[0].FindControl("txtEmp_ln");
System.Web.UI.WebControls.TextBox txtEmp_phone = (System.Web.UI.WebControls.TextBox)DataGridView1.Controls[0].Controls[0].FindControl("txtEmp_phone");
System.Web.UI.WebControls.TextBox txtEmp_email = (System.Web.UI.WebControls.TextBox)DataGridView1.Controls[0].Controls[0].FindControl("txtEmp_email");
MySqlConnection conn = new MySqlConnection(connection);
MySqlCommand cmd = new MySqlCommand();
cmd.Connection = conn;
cmd.CommandText = "insert into employees(Emp_number,First_name,Last_name,Phone_num,Email) values(@1,@2,@3,@4,@5)";
cmd.Parameters.AddWithValue("@1", txtEmp_num.Text);
cmd.Parameters.AddWithValue("@2", txtEmp_fn.Text);
cmd.Parameters.AddWithValue("@3", txtEmp_ln.Text);
cmd.Parameters.AddWithValue("@4", txtEmp_phone.Text);
cmd.Parameters.AddWithValue("@5", txtEmp_email.Text);
conn.Open();
cmd.ExecuteNonQuery();
conn.Close();
Bind();
}
catch (Exception ex)
{
MessageBox.Show(ex.Message);
}
}
}
尝试'调试'代码,看看哪个控件是'null' .. – mmushtaq
请参阅http://stackoverflow.com/a/4660186/5836671 – VDWWD