发送数据与机器人

Question

交方法这是我使用的代码：

   HttpClient client = new DefaultHttpClient(); 
       HttpPost method = new HttpPost("http://192.168.1.1/value/_0/_0"); 
       JSONObject object = new JSONObject(); 
       try { 
        object.put("Val", "0"); 
        msg = object.toString(); 
        method.addHeader(BasicScheme.authenticate(new UsernamePasswordCredentials("admin", "00000000"), "UTF-8", false)); 
        method.setHeader("Content-Type", "application/json"); 
        method.setEntity(new StringEntity(msg, "UTF8")); 
        client.execute(method); 
       } 
       catch (IOException e) { 
        e.printStackTrace(); 
       } 
       catch (Exception e) { 
        e.printStackTrace(); 
       } 

这里我加入用于认证目的和内容类型的请求报头。这在我不知道什么是错误的。

Answer 1

这样做：

public static String postJson(String sUrl, String jsonParams){ 
    String response = ""; 
    try { 
     HttpURLConnection conn; 
     //just encoding space from url 
     URL url = new URL(sUrl.replace(" ", "%20")); 
     conn = (HttpURLConnection) url.openConnection(); 
     conn.setRequestMethod("POST"); 
     conn.setRequestProperty("content-type", "application/json"); 

     byte[] outputInBytes = jsonParams.getBytes("UTF-8"); 
     OutputStream os = conn.getOutputStream(); 
     os.write(outputInBytes); 
     os.close(); 
     conn.connect(); 

     if (conn.getResponseCode() == HttpURLConnection.HTTP_OK) { 
     InputStream inputStream = conn.getInputStream(); 
     response = convertStreamToString(inputStream); 
     } 

     Log.e("Request: ", sUrl+jsonParams+""); 
     Log.e("Response: ", response+""); 
    } catch (IOException e) { 
     e.printStackTrace(); 
    } 
    return response; 
} 

public static String convertStreamToString(InputStream inputStream) { 
    if (inputStream == null) 
     return null; 
    StringBuilder sb = new StringBuilder(); 
    try { 
     BufferedReader r = new BufferedReader(new InputStreamReader(inputStream), 1024); 
     String line; 
     while ((line = r.readLine()) != null) { 
     sb.append(line); 
     } 
    } catch (Exception e) { 
     e.printStackTrace(); 
    } 
    return sb.toString(); 
} 

对于更详细的检查：GET and POST request

Answer 2

您需要使用的URLConnection和DefaultHttpClient（）现在已经过时。

public String performPostCall(String requestURL, 
    HashMap<String, String> postDataParams) { 

URL url; 
String response = ""; 
try { 
    url = new URL(requestURL); 

    HttpURLConnection conn = (HttpURLConnection) url.openConnection(); 
    conn.setReadTimeout(15000); 
    conn.setConnectTimeout(15000); 
    conn.setRequestMethod("POST"); 
    conn.setDoInput(true); 
    conn.setDoOutput(true); 


    OutputStream os = conn.getOutputStream(); 
    BufferedWriter writer = new BufferedWriter(
      new OutputStreamWriter(os, "UTF-8")); 
    writer.write(getPostDataString(postDataParams)); 

    writer.flush(); 
    writer.close(); 
    os.close(); 
    int responseCode=conn.getResponseCode(); 

    if (responseCode == HttpsURLConnection.HTTP_OK) { 
     String line; 
     BufferedReader br=new BufferedReader(new InputStreamReader(conn.getInputStream())); 
     while ((line=br.readLine()) != null) { 
      response+=line; 
     } 
    } 
    else { 
     response="";  

    } 
} catch (Exception e) { 
    e.printStackTrace(); 
} 

return response; 

}