Question

我必须从MySQL数据库开发一个XML提要使用PHP代码..我必须插入或更新我的MySQL数据库上的任何数据意味着插入和更新的数据自动更改并插入我的xml饲料也无需刷新页面。我可以开发this.please帮助我。

我用下面的代码：

$catname=func_query_first_cell("select status from $sql_tbl[orders] where status='Q'"); 
    $file= fopen("orderdetails1.xml", "w");   
    $_xml ="<?xml version=\"1.0\" encoding=\"ISO-8859-1\" ?>\r\n"; 
    $_xml .="\t<Feed>\r\n"; 
    $_xml .="\t<order>\r\n"; 

$_xml .="\t<status>" .htmlspecialchars($catname,ENT_QUOTES). "</status>\r\n"; 
$page = (int) (!isset($_GET["page"]) ? 1 : $_GET["page"]); 
$limit = 2; 
$startpoint = ($page * $limit) - $limit; 
$statement = "`xcart_orders` where `active` = 1";  
$counterr=0; 
$r=func_query("select * from $sql_tbl[orders] LIMIT {$startpoint}, {$limit}"); 
foreach($r as $n) 
{ 
$products=func_query_first("select * from $sql_tbl[orders] where status='Q'"); 
$products=func_query_first("select product from $sql_tbl[order_details] where orderid=$n[orderid]"); 

$infeed_counter++; 

echo $manufacturer."====="; 

if($row[avail]>0) 
       $avail='Y'; 
      else 
       $avail='N'; 


$_xml .="\t<Order>\r\n"; 
    $_xml .="\t<orderid>" .$n[orderid]. "</orderid>\r\n"; 
    $_xml .="\t<login>" . htmlspecialchars(strip_tags(substr($n[login],0,50)) , ENT_QUOTES). "</login>\r\n"; 
$_xml .="\t<total>" . $n[total]. "</total>\r\n"; 
    $_xml .="\t<product>" . $products[product]. "</product>\r\n"; 
    $_xml .="\t</Order>\r\n"; 
} 

    $_xml .="\t</order>\r\n"; 
    $_xml .="\t</Feed>\r\n";  
fwrite($file, $_xml);  
fclose($file);  
echo "XML version of products available here with $infeed_counter products. <a href=\"orderdetails1.xml?page=$page\">View the XML.</a>"; 
    exit; 
    ?> 

现在，我得到下面的XML提要：

<Feed> 
<order> 
<status>Q</status> 
<Order> 
    <orderid>1</orderid> 
     <login>krishna</login> 
     <total>399.99</total> 
     <product>Designing Web Usability</product> 
</Order> 
<Order> 
     <orderid>65</orderid> 
     <login>krishna</login> 
     <total>399.99</total> 
     <product>Three Stone Princess Cut Diamond Ring</product> 
    </Order> 
<Order> 
      <orderid>2</orderid> 
      <login>krishna</login> 
      <total>34.65</total> 
      <product>Three Stone Princess Cut Diamond Ring</product> 
</Order> 

现在我想总的399.99更改为500.00订单id = 1我的MySQL数据库意味着必须刷新page.then只有我的xml饲料在这里改变。但我希望需要的解决方案是数据库更改是自动更新我的xml饲料而不刷新页面。请帮助我。我可以开发这个。

Answer 1

尝试这样的： feed.php

$catname = func_query_first_cell("select status from $sql_tbl[orders] where status='Q'"); 
$file = fopen("orderdetails1.xml", "w"); 
$_xml = "<?xml version=\"1.0\" encoding=\"ISO-8859-1\" ?>"; 
$_xml .= "<Feed>"; 
$_xml .= "<order>"; 

$_xml .= "<status>" . htmlspecialchars($catname, ENT_QUOTES) . "</status>"; 
$page = (int)(!isset($_GET["page"]) ? 1 : $_GET["page"]); 
$limit = 2; 
$startpoint = ($page * $limit) - $limit; 
$statement = "`xcart_orders` where `active` = 1"; 
$counterr = 0; 
$r = func_query("select * from $sql_tbl[orders] LIMIT {$startpoint}, {$limit}"); 
foreach ($r as $n) 
{ 
    $products = func_query_first("select * from $sql_tbl[orders] where status='Q'"); 
    $products = func_query_first("select product from $sql_tbl[order_details] where orderid=$n[orderid]"); 

    $infeed_counter++; 

    // echo $manufacturer."====="; 

    if ($row[avail] > 0) 
     $avail = 'Y'; 
    else 
     $avail = 'N'; 


    $_xml .= "<Order>"; 
    $_xml .= "<orderid>" . $n[orderid] . "</orderid>"; 
    $_xml .= "<login>" . htmlspecialchars(strip_tags(substr($n[login], 0, 50)), ENT_QUOTES) . "</login>"; 
    $_xml .= "<total>" . $n[total] . "</total>"; 
    $_xml .= "<product>" . $products[product] . "</product>"; 
    $_xml .= "</Order>"; 
} 

$_xml .= "</order>"; 
$_xml .= "</Feed>"; 

header ("Content-Type:text/xml"); 
echo $_xml; 

在这样的XML提要URL访问

：

http://www.exampleyourdoamin/feed.php

Answer 2

您需要使用称为长轮询的技术。长时间轮询会使连接保持打开一段时间。在此期间，它会检查数据库中是否有任何更改。如果是，它会中断连接并将这些更改发送到前端。然后立即开始另一个连接。你会在这里找到更多的信息。 http://techoctave.com/c7/posts/60-simple-long-polling-example-with-javascript-and-jquery