无法使用xpath查找实时更新字段的元素

Question

每次在选择实时更新字段时请求标识发生更改。

正尝试通过的XPath

这让请求ID是源代码。

<form id="itemscreen334-33504-" class="itemscreen addMode v_334 ajaxForm form-initialized" method="POST" enctype="multipart/form-data" requestid="18310" style="visibility: visible; opacity: 1;"> 

Java代码：

WebElement form = driver.findElement(By.xpath("//form[Class='itemscreen addMode v_334 ajaxForm form-initialized')]")); 
System.out.println("form-->" + form); 
String requestNo = form.getAttribute("requestid"); 
System.out.println("requestNo----------->" + requestNo); 

硒错误：

Exception in thread "main" org.openqa.selenium.InvalidSelectorException: The given selector //form[Class='itemscreen addMode v_334 ajaxForm form-initialized')] is either invalid or does not result in a WebElement. The following error occurred: InvalidSelectorError: Unable to locate an element with the xpath expression //form[Class='itemscreen addMode v_334 ajaxForm form-initialized')] because of the following error: [Exception... "The expression is not a legal expression." code: "12" nsresult: "0x805b0033 (SyntaxError)" location: ""]

？我怎样才能使用XPath请求ID？

Answer 1

其实你提供错误xpath，你xpath表情貌似cssSelector，如下尝试： -

WebElement form = driver.findElement(By.cssSelector("form.itemscreen.addMode.v_334.ajaxForm.form-initialized")); 
String requestNo = form.getAttribute("requestid"); 
System.out.println("requestNo----------->" + requestNo); 

或者，如果你想使用xpath尝试用正确xpath如下： -

WebElement form = driver.findElement(By.xpath("//form[@class = 'itemscreen addMode v_334 ajaxForm form-initialized']")); 
String requestNo = form.getAttribute("requestid"); 
System.out.println("requestNo----------->" + requestNo); 

注意：如果您想要与class属性部分匹配，您应该使用xpath as By.xpath("//form[contains(@class, 'itemscreen addMode')]") and cssSelector as By.cssSelector("form.itemscreen.addMode")